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It is easier to prove that almost all real numbers are normal than to prove that any particular real number is normal.

Indeed, none of the most natural candidates, such as $\sqrt{2}$, $\pi$ or $e$, has yet been proved normal.

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It is easier to prove that almost all real numbers are normal than to prove that any particular real number is normal.

show/hide this revision's text 1 [made Community Wiki]

It is easier to prove that almost real numbers are normal than to prove that any particular real number is normal.