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Context

Consider the following sequential data generating process for $Y_1$, $Y_2$, $Y_3$. (By sequential I mean that we generate $Y_1$, $Y_2$, $Y_3$ in sequence.):

$Y_1 = X_1^' \beta + \epsilon$ epsilon_1$

$Y_2 = X_2^' \beta + \epsilon$ epsilon_2$

$Y_3 = X_3^' \beta + \epsilon$ epsilon_3$

where,

$X_3 = x_{3,1}^'$ x_{3,1}$ if $y_1$ $y_2$ > 0,

OR

$X_3 = x_{3,2}^'$ x_{3,2}$ if $y_1$ $y_2$ < 0,

$\epsilon$ is \epsilon_i$, ($i$ = 1, 2, 3) are i.i.d $N(0,\sigma^2)$,

$\beta$ is a $p x 1$ vector and

$X_1$, $X_2$, and $X_3$ are vectors of appropriate dimensions.

Question

Suppose we observe the following sequence: {$Y_1$ = $y_1$,$Y_2$ = $y_2$, $X_{31}$ X_3$ = $x_{31}$, $Y_3$ = $y_3$} and wish to estimate the parameters $\beta$ and $\sigma$. Is the likelihood function given below the correct function?

L( $\beta$, $\sigma$ | $y_1$, $y_2$, $y_3$, $x_1$, $x_2$, $x_{31}$ ) = ( $f(y_1|x_1,\beta, \sigma)$ $f(y_2|x_2,\beta, \sigma)$ $f(y_3|x_{31},\beta, \sigma)$ ) / Prob( $Y_1 Y_2 >0 $ )

Thanks

EDIT: Fixed some typos and notation in light of comments by Bjørn.

show/hide this revision's text 3 added 5 characters in body

Context

Consider the following sequential data generating process for $Y_1$, $Y_2$, $Y_3$. (By sequential I mean that we generate $Y_1$, $Y_2$, $Y_3$ in sequence.):

$Y_1 = X_1^' \beta + \epsilon$

$Y_2 = X_2^' \beta + \epsilon$

$Y_3 = X_3^' \beta + \epsilon$

where,

$X_3 = x_{3,1}^'$ if $y_1$ $y_2$ > 0,

OR

$X_3 = x_{3,2}^'$ if $y_1$ $y_2$ < 0,

$\epsilon ~\epsilon$ is $N(0,\sigma^2)$,

$\beta$ is a $p x 1$ vector and

$X_1$, $X_2$, and $X_3$ are vectors of appropriate dimensions.

Question

Suppose we observe the following sequence: {$Y_1$ = $y_1$,$Y_2$ = $y_2$, $X_{31}$ = $x_{31}$, $Y_3$ = $y_3$} and wish to estimate the parameters $\beta$ and $\sigma$. Is the likelihood function given below the correct function?

L( $\beta$, $\sigma$ | $y_1$, $y_2$, $y_3$, $x_1$, $x_2$, $x_{31}$ ) = ( $f(y_1|x_1,\beta, \sigma)$ $f(y_2|x_2,\beta, \sigma)$ $f(y_3|x_{31},\beta, \sigma)$ ) / Prob( $Y_1 Y_2 >0 $ )

Thanks

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