For closed n-manifolds M and N with the form $M\simeq M^{n-1}\cup _{f}e^n $,$N\simeq N^{n-1}\cup _{d}e^6${d}e^n$
Why $M\sharp N \simeq (M^{n-1}\vee N^{n-1})\cup _{f+d}e^6$?{f+d}e^n$?
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For closed n-manifolds M and N with the form $M\simeq M^{n-1}\cup _{f}e^n$ and {f}e^n $N\simeq ,$N\simeq N^{n-1}\cup {d}e^6$,\ _{d}e^6$ Why $M\sharp N\simeq N \simeq (M^{n-1}\vee N^{n-1})\cup {f+d}e^6$?_{f+d}e^6$? |
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Homotopy type of connected sum of certain manifoldsFor closed n-manifolds M and N with the form $M\simeq M^{n-1}\cup _{f}e^n$ and $N\simeq N^{n-1}\cup {d}e^6$,\ Why $M\sharp N\simeq (M^{n-1}\vee N^{n-1})\cup {f+d}e^6$?
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