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Hi everyone, I would like to find a function $$\Psi: z\in\mathbb{R}\rightarrow\mathbb{R_+}$$$\Psi\in\mathcal{C}^2: z\in\mathbb{R}\rightarrow\Psi(z)\in\mathbb{R_+}$$ satisfying the following conditions: $$1-\frac{z\Psi'(z)}{\Psi(z)}+8s\Psi''(z)\geq 0$$ $$\Psi(z)^2+\frac{4}{\theta}\Psi(z)\leq\frac{z^2}{4\theta s}$$ where $\theta$, $s$ are given positive constants. The second inequality yields $$0<\Psi(z)\leq\sqrt{\frac{z^2}{4\theta $0\leq\Psi(z)\leq\sqrt{\frac{z^2}{4\theta s}+\frac{4}{\theta^2}}-\frac{2}{\theta}$$ Could someone have an idea to solve the first differential equation? Or give such a function $\Psi(z)$? Many thanks! |
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search for a function satisfying some conditionsHi everyone, I would like to find a function $$\Psi: z\in\mathbb{R}\rightarrow\mathbb{R_+}$$ satisfying the following conditions: $$1-\frac{z\Psi'(z)}{\Psi(z)}+8s\Psi''(z)\geq 0$$ $$\Psi(z)^2+\frac{4}{\theta}\Psi(z)\leq\frac{z^2}{4\theta s}$$ where $\theta$, $s$ are given positive constants. The second inequality yields $$0<\Psi(z)\leq\sqrt{\frac{z^2}{4\theta s}+\frac{4}{\theta^2}}-\frac{2}{\theta}$$ Could someone have an idea to solve the first differential equation? Or give such a function $\Psi(z)$? Many thanks!
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