Take the graph $z=\sqrt{x^2+y^2}$ t=\sqrt{x^2+y^2+z^2}$with induced intrinsic metric. In$(x,y)$-coordinates, (x,y,z)$-coordinates, the scalar curvature is $$\frac C{x^2+y^2}.$$C{x^2+y^2+z^2}.$$Are you happy? 2 added 9 characters in body Take the graph z=|x+y| z=\sqrt{x^2+y^2} with induced intrinsic metric. In (x,y)-coordinates, the scalar curvature is$$\frac C{|x+y|^2}.$$C{x^2+y^2}.$$
Take the graph $z=|x+y|$ with induced intrinsic metric. In $(x,y)$-coordinates, the scalar curvature is $$\frac C{|x+y|^2}.$$