Take the graph $z=\sqrt{x^2+y^2}$ t=\sqrt{x^2+y^2+z^2}$ with induced intrinsic metric. In $(x,y)$-coordinates, (x,y,z)$-coordinates, the scalar curvature is $$\frac C{x^2+y^2}.$$C{x^2+y^2+z^2}.$$
Are you happy?
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Take the graph $z=\sqrt{x^2+y^2}$ t=\sqrt{x^2+y^2+z^2}$ with induced intrinsic metric. In $(x,y)$-coordinates, (x,y,z)$-coordinates, the scalar curvature is $$\frac C{x^2+y^2}.$$C{x^2+y^2+z^2}.$$ Are you happy? |
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Take the graph $z=|x+y|$ z=\sqrt{x^2+y^2}$ with induced intrinsic metric. In $(x,y)$-coordinates, the scalar curvature is $$\frac C{|x+y|^2}.$$C{x^2+y^2}.$$ Are you happy? |
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Take the graph $z=|x+y|$ with induced intrinsic metric. In $(x,y)$-coordinates, the scalar curvature is $$\frac C{|x+y|^2}.$$ Are you happy? |
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