|
4 | added 260 characters in body | ||
|
$\mathbb{Z}\subset A=\mathbb{Z}\subset \mathbb R^2$. In this case $\partial\mathbb{Z}= \mathbb{Z}$ and $\mathop{Leb}^+(\mathbb Z)=\infty$ and $H^1(\mathbb Z)=0$. You can get a bounded example of the same type. Take a countable nowhere dense set $A$ in the unit disc such that the $\varepsilon$-neighborhood of $A$ contains a disc of radius $\sqrt[3]{\varepsilon}$. |
||||
|
Post Undeleted by Anton Petrunin
|
||||
|
|
||||
|
|
3 | deleted 76 characters in body; added 73 characters in body | ||
|
$\mathbb Q\subset \mathbb{Z}\subset \mathbb R^2$. $\mathop{Leb}^+(\mathbb Q)=\infty$ Z)=\infty$ and $H^1(\mathbb Q)=0$.Z)=0$ |
||||
|
Post Deleted by Anton Petrunin
|
||||
|
2 | added 61 characters in body | ||
|
Post Undeleted by Anton Petrunin
|
||||
|
Post Deleted by Anton Petrunin
|
||||
|
|
1 |
|
||
