Questions tagged [smooth-manifolds]

Smooth manifolds and smooth functions between them. For manifolds with additional structure, see more specific tags, such as [riemannian-geometry]. For more topological aspects, see [differential-topology].

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Which spherical space forms embed in $S^4$?

Is there any hope of getting a classification of which 3-dimensional spherical space forms are smoothly embeddable in $S^4$? I read that lens spaces cannot embed in $S^4$, but some other spherical ...
Topology Student's user avatar
14 votes
0 answers
545 views

Reference for a proof of the fiberwise Stokes theorem

The fiberwise Stokes theorem says that given a differential form on a smooth fiber bundle whose fibers have boundary, the difference between the fiberwise integral of the differential and the ...
Dmitri Pavlov's user avatar
13 votes
2 answers
2k views

Can a simply connected manifold satisfy $𝑀\simeq 𝑀\times 𝑀$?

Let $M$ be a simply connected, (finite dimensional) smooth manifold. Is it possible that $M$ is homotopy equivalent to $M\times M,$ without $M$ being contractible? This would imply $\pi_n(M)\times\...
Josh Lackman's user avatar
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13 votes
2 answers
2k views

Spectrum of Ring of Smooth Functions on $\mathbb{R}^n$

When we define smooth manifold, we starting with topological space $M$ which localy homeomorphic to $\mathbb{R}^n$ and setting up sheaf $\mathscr{F}(M)$ of functions on it which localy isomorphic to $\...
Chilly Willy's user avatar
13 votes
4 answers
2k views

The Schwartz Space on a Manifold

I asked this question a couple of days ago on math.stackexchange, but have yet to receive a response, so I have decided to post this here. This question is also vaguely related (both questions arose ...
Jonathan Gleason's user avatar
13 votes
3 answers
1k views

How to disjoint two cycles with zero intersection?

Suppose that $M^n$ is a smooth connected orientable manifold and $Z^k$ with $Z^{n-k}$ are two real cycles in $M^n$ with zero index of intersection $Z^k\cdot Z^{n-k}=0$ (these cycles are submanifolds ...
aglearner's user avatar
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13 votes
2 answers
719 views

Can every element of a homotopy group of a smooth manifold be represented by an immersion?

I originally posted this on MSE but didn't get much of a response, so I'll attempt to post it here. Let me know if this is not appropriate. Let $M$ be a smooth manifold of dimension $n$. Let $\alpha \...
Paul Cusson's user avatar
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13 votes
3 answers
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What is the characteristic property of surjective submersions?

In Lee's Introduction to smooth manifolds he states that given smooth manifolds $X,Y$ and a surjective submersion, $f:X \rightarrow Y$, then $f$ is a smoothly final map, that is for any further smooth ...
Mozibur Ullah's user avatar
13 votes
1 answer
533 views

Identifying two definitions of orientation on a vector space

Let $V$ be an $n$-dimensional real vector space. Here are two definitions of an orientation on $V$: A generator of the $1$-dimensional vector space $\wedge^n V$, up to multiplication by positive ...
Jean's user avatar
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13 votes
2 answers
689 views

Given a Kirby diagram of a 4-manifold, what's its homotopy 2-type?

It's easy to derive a presentation of the fundamental group of a 4-manifold if you have a Kirby diagram: The 1-handles are generators and the 2-handles are the relations. The 3- and 4-handles, which ...
Manuel Bärenz's user avatar
13 votes
1 answer
584 views

Are there examples of Einstein manifolds with unbounded curvature?

Are there any known examples of Einstein manifolds $(M, g)$ such that $$\sup_{x \in M} \|\text{Rm}(x) \| = \infty$$ I'm looking for these examples because they might provide a counter-example to a ...
Matheus Andrade's user avatar
13 votes
0 answers
174 views

Is there a Handle Approximation theorem?

The cellular approximation theorem states that given a continuous map between two CW complexes $f : X \to Y$, then $f$ is homotopic to a cellular map - that is some map $f'$ with $f'(X_n) \subset Y_n$ ...
user101010's user avatar
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12 votes
3 answers
839 views

$A_{\infty}$-structure on closed manifold

Is there an exmaple of a closed smooth connected manifold $M$ having a structure of $A_{\infty}$-space (with unit) but $M$ is not homeomorphic to a compact connectd Lie group as space ? Edit: First, ...
Ilias A.'s user avatar
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12 votes
2 answers
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Stokes' theorem etc., for non-Hausdorff manifolds

This question is prompted by another one. I want to motivate the definition of a scheme for people who know about manifolds(smooth, or complex analytic). So I define a manifold in the following way. ...
Anweshi's user avatar
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12 votes
3 answers
2k views

In Diff, are the surjective submersions precisely the local-section-admitting maps?

Question as in title (Diff = category of smooth manifolds and smooth maps) I thought I'd convinced myself this is true, so this is just a sanity check. Also, what about for settings other than ...
David Roberts's user avatar
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12 votes
5 answers
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Which manifolds admit a diffeomorphism of order $n$?

Let $n>1$. Which smooth manifolds admit a diffeomorphism $f$ of order $n$? For a closed orientable surface $S_g$ of genus $g$ and $n=2$ the answer is in the affirmative, since $S_g$ can be ...
Łukasz Garncarek's user avatar
12 votes
1 answer
804 views

Manifolds with nonwhere vanishing closed one forms

I am trying to find examples of closed manifolds $M$ admitting a nowhere vanishing closed one form. I am wondering if there are any examples beyond $N\times S^1$.
ZZY's user avatar
  • 707
12 votes
3 answers
1k views

Is the class of n-dimensional manifolds essentially small?

Question: Consider the proper class of all $n$-dimensional smooth manifolds. If we take the equivalence classes where two manifolds are identified if there exists a diffeomorphism between them, is ...
Willie Wong's user avatar
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12 votes
3 answers
953 views

Fixed point set of smooth circle action

Suppose $M$ is a connected closed smooth $d$-dimensional manifold, and suppose $S^1 = SO(2)$ acts smoothly on $M$. Then the fixed point set $Y = M^{S^1}$ will be a submanifold of $M$ of even ...
Jens Reinhold's user avatar
12 votes
4 answers
2k views

Book on manifolds from a sheaf-theoretic/locally ringed space PoV

I'm looking for an introductory (or rather, non-advanced) book on manifolds as locally ringed spaces, i.e., from the algebraic geometric viewpoint. Most introductory texts only introduce manifolds ...
xuq01's user avatar
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12 votes
3 answers
3k views

Symmetric and anti-symmetric parts of the covariant derivative of a connection

The following is an excerpt from Sharpe's Differential Geometry - Cartan's Generalization of Klein's Erlangen Program. Now we come to the question of higher derivatives. As usual in modern ...
Arrow's user avatar
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12 votes
2 answers
762 views

Topological obstructions to existence of immersion

Let $M$ be a smooth, non-compact manifold. a) Can one always find a smooth, compact manifold $N$ with $\dim(N) = \dim(M)$ and a smooth embedding $i: M \to N$ ? b) If not, are there some concrete ...
H1ghfiv3's user avatar
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12 votes
7 answers
1k views

Cohomology classes annihilated by pullbacks

A friend of mine is interested in examples of the following situation: an oriented smooth fiber bundle $\pi \colon M \to B$ with $M$ and $B$ compact and a non-zero class $a \in H^3(B; \mathbb{Q})$ ...
Petya's user avatar
  • 4,696
12 votes
1 answer
1k views

Intuitive Aproach to Dolbeault Cohomology [closed]

(Duplicated from math.stackexchange) I would like to understand an intuitive approach to the definitions of Dolbeault Cohomology (using $\partial$ and $\bar{\partial}$) similar to the one given here. ...
Jjm's user avatar
  • 2,071
12 votes
1 answer
703 views

Homotopy spheres with vanishing and non-vanishing $\alpha$-invariant

I'm unsure whether this question is appropriate for mathoverflow, so feel free to criticize. All manifolds are closed, smooth and have dimensions $n\ge 5$. The Atiyah-Shapiro-Bott-Orientation gives ...
archipelago's user avatar
  • 2,954
12 votes
2 answers
506 views

Homeo-Fixed point property

Edit: According to comment of Michał Kukieła I revised the question A topological space $X$ satisfies "Homeo-fixed point" property if every homeomorphism $f$ on $X$ possess a fixed point. ...
Ali Taghavi's user avatar
12 votes
2 answers
550 views

Self homeomorphisms of $S^2\times S^2$

Every matrix $A\in SL_2(\mathbb{Z})$ induces a self homeomorphism of $S^1\times S^1=\mathbb{R}^2/\mathbb{Z}^2$. For different matrices these homeomorphisms are not homotopic, as the induced map on $\...
HenrikRüping's user avatar
12 votes
2 answers
2k views

What is the infinite-dimensional-manifold structure on the space of smooth paths mod thin homotopy?

This question is motivated by the recent paper An invitation to higher gauge theory by Baez and Huerta, and the 2007 paper Parallel Transport and Functors by Schreiber and Waldorf. Let $M$ be a ...
Theo Johnson-Freyd's user avatar
12 votes
3 answers
3k views

Non-Lie Subgroups

A result of Borel and Lichnerowicz states that the holonomy group of a connection on a principal $G$-bundle is a Lie subgroup of $G$ (Cartan had earlier asserted this, but apparently without proof). ...
Harold Williams's user avatar
12 votes
1 answer
301 views

Approximate classifying space by boundaryless manifolds?

As pointed out by Achim Krause, any finite CW complex is homotopy equivalent to a manifold with boundary (by embedding into $\mathbb R^n$ and thickening), and so every finite type CW complex can be ...
0207's user avatar
  • 123
12 votes
2 answers
3k views

Derivative of the flow for ODEs on manifolds

Let $\mathbf V \colon [0,T] \times \mathbb R^d \to \mathbb R^d$ (for $T>0$) be a given, bounded smooth vector field and let $\mathbf X=\mathbf X(t,x)$ be its flow, i.e. the unique solution to the ...
user111164's user avatar
12 votes
1 answer
389 views

Are algebras of smooth functions formally smooth?

Let $M$ be a manifold. Then is the ring of smooth functions $C^\infty(M,\mathbb{R})$ formally smooth over $\mathbb{R}$? If it helps, feel free to assume that $M$ is compact. (This is not a joke ...
Tobias Fritz's user avatar
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12 votes
2 answers
353 views

Is $C^r(M)$ non-isomorphic to $C^s(N)$ for $r\neq s$ and nontrivial manifolds $M,N$?

This is an obvious continuation of an MO question. Let $r,s\in\mathbb N\cup\{\infty\}$ with $r\neq s$, and $M,N$ two connected manifolds of positive dimension (which roots out the trivial case of a ...
Z. M's user avatar
  • 2,003
12 votes
1 answer
252 views

Homotopies with prescribed regular values

Let $M_1$ and $M_2$ be connected smooth manifolds and let $f_0,f_1:M_1 \rightarrow M_2$ be homotopic smooth maps such that some fixed point $p \in M_2$ is a regular value for both $f_0$ and $f_1$. ...
Lisa's user avatar
  • 321
12 votes
0 answers
255 views

Smooth dual cell structure

Let us consider a closed oriented smooth manifold M. It is well known that a smooth combinatorial triangulation can be constructed for it. That is to say, a homeomorphism from the geometric ...
Anibal Medina's user avatar
12 votes
0 answers
403 views

The $\infty$-category of $n$-manifolds and open embeddings determined homotopically from that of topological manifolds?

Let $\mathrm{Diff}_n$, $\mathrm{PL}_n$, $\mathrm{Top}_n$ denote the $\infty$-categories of $n$-manifolds which are respectively smooth/PL/topological, and open embeddings (for instance by taking the ...
Saal Hardali's user avatar
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12 votes
0 answers
377 views

Two ways a manifold can have little symmetry

Let $M$ be a closed connected smooth oriented manifold. The following two properties - that $M$ can either enjoy or not - intuitively both mean that $M$ has very little symmetry: (a) Every self-map $...
Jens Reinhold's user avatar
12 votes
0 answers
479 views

Exotic smoothness and Parallelizability

Regarding the parallelizability of the Milnor's seven dimensional exotic spheres: Parallelizability of the Milnor's exotic spheres in dimension 7 The following question naturally arises: Suppose ...
Hamed's user avatar
  • 1,226
11 votes
3 answers
2k views

Is each closed convex set a manifold with corners?

Assume that $C$ is a convex set in $\mathbb{R}^{n}$ with non empty interior. Then consider its closure, is it a smooth manifold with corners? Edit: 1) The closure of $C$ should be a smooth manifold ...
Cepu's user avatar
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11 votes
5 answers
2k views

Ricci Curvature in infinite dimensions?

Is there a good notion of "Ricci curvature" in infinite dimensions? My intuitive understanding of Ricci curvature is that it is some kind of an "average" of the curvature tensor over "different ...
BrainDead's user avatar
  • 235
11 votes
1 answer
843 views

Critical dimensions D for "smooth manifolds iff triangulable manifolds"

I am aware that at least for lower dimensions, "smooth manifolds iff triangulable manifolds" at least for dimensions below a certain critical dimensions D. My question is that for For ...
wonderich's user avatar
  • 10.3k
11 votes
2 answers
306 views

Triangulation with simplices of same volume

Let $M$ be a Riemannian smooth compact manifold. It is known that $M$ has a triangulation, for any dimension. But do we know if there exists a triangulation such that all simplices have same volume ? ...
Thibault Lefeuvre's user avatar
11 votes
1 answer
2k views

Finite-dimensionality for de Rham cohomology

I was browsing through the litterature, hoping to find sufficient and necessary conditions for a smooth manifold to have finite-dimensional de Rham cohomology, but I can't find any satisfactory answer....
M Turgeon's user avatar
  • 397
11 votes
2 answers
714 views

The ring $C^{\infty}(M)$?

Let $M$ be a smooth paracompact manifold. I think that the ring $C^{\infty}(M)$ contains many (possibly almost all?) geometric or topological information about $M$. (e.g. Let $E$ be a vector bundle ...
Topologieee's user avatar
11 votes
1 answer
381 views

Twisting bordism classes

Let $X$ be a reasonable topological space (I'd be happy to assume that $X$ is a smooth closed manifold) and let $f\colon M^n \rightarrow X$ be a continuous map from a smooth oriented $n$-manifold $M^n$...
Sarah's user avatar
  • 113
11 votes
3 answers
957 views

Waldhausen $K$-theory for $G$-spaces

I would guess that the following is true, and that somebody has worked it out, but I don't recall ever seeing it. Can anyone point me to any literature on it? Let $G$ be a finite group. We know that ...
Tom Goodwillie's user avatar
11 votes
1 answer
877 views

Smooth four-manifolds with contractible universal cover

Let $X$ be a smooth compact four-manifold with definite non-trivial intersection form. Can the universal cover of $X$ be contractible? It semms to me that the answer is negative when $X$ is simply ...
Matei's user avatar
  • 123
11 votes
1 answer
2k views

Does pullback in the category of smooth manifolds always exists?

I am looking for an example where $f:Y\to X$ and $f':Y'\to X$, are both smooth maps of smooth manifolds, but the pullback does not exist. Remarks: 1) A pullback in a certain category is defined as ...
Asaf Shachar's user avatar
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11 votes
1 answer
324 views

Does the Lie algebra of vector fields $\mathfrak{X}(M)$ determine the diffeomorphism class of a manifold $M$?

Let $M_1,M_2$ be two simply connected, connected, compact smooth manifolds without boundary and of the same dimension. Assume that $\mathfrak{X}(M_1)\cong \mathfrak{X}(M_2)$ as Lie algebras. ...
Amr's user avatar
  • 1,025
11 votes
1 answer
550 views

Examples of 6-manifolds without an almost complex structure

Question: I am searching for examples for closed (hence orientable ), smooth $6$-manifolds without an almost complex structure. Finding such an example is equivelant to finding a manifold where the ...
Nick L's user avatar
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