Questions tagged [ra.rings-and-algebras]

Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

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Associative rings with "big" commutative subrings

Let $A$ be an associative ring and $R\subset A$ be a commutative subring. Suppose that every element of $A$ has the form $urv$ where $r\in R$ and $u, v\in A^*$ are invertible. A basic example is $A=...
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Decomposition of augmentation ideal in a group ring

Let $R$ be a ring and $G$ be a finite group with invertible order in $R$. Assume that the augmentation ideal $\Delta (G)$ of group ring $RG$ has a decomposition $M_1\oplus M_2\oplus \cdots M_k$ as an $...
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Are PD-, $\lambda$-, $\psi$-, and $\delta$-rings monoids in a monoidal category?

$\newcommand{\pt}{\mathrm{pt}}\newcommand{\N}{\mathbb{N}}\newcommand{\Z}{\mathbb{Z}}$A number of algebraic structures can be defined as monoids in some appropriate monoidal category: A monoid ...
Emily's user avatar
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Question about terminology for a class of "self-modular" mappings between rings

(In the scenario I have in mind, rings need not be unital.) The following notion has come up in some joint work that is being written up. Let $R$ and $S$ be rings, and let $D$ be a subring of $R$. Is ...
Yemon Choi's user avatar
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Is the group ring of an amenable group, viewed as multiplicative monoid, amenable?

Motivated by this question, it seems natural to ask the following: Question 1: Is there a [finitely generated discrete] torsion-free virtually Abelian (but not Abelian) group $G$ so that the ...
ARG's user avatar
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Are there any 1-decidable algebraic extensions of $\mathbb{Q}$ which are not decidable?

A model $M$ is decidable if the set of all first-order formulas which are true in $M$ is a recursive set. And a model is $1$-decidable if the set of all existential formulas which are true in $M$ is ...
Keshav Srinivasan's user avatar
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Do you know rings without involutions, auto-anti-isomorphics? In that case, what is the minimal example?

Do you know rings without involutions, but auto-anti-isomorphic (isomorphic to their opposite)? In that case, what is the minimal example? If a ring has an involution f, then f is an anti-automorphism;...
José María Grau Ribas's user avatar
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Finding all nice ideals for quiver algebras

Let $Q$ be a finite, connected and acyclic quiver which is simply-laced. Let $k$ be a field and $kQ$ the path algebra of $Q$ over $k$. Recall that an ideal $I$ of $kQ$ is called admissible if it is ...
Mare's user avatar
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When adic completion preserves projectives?

Lets take a ring $R$ and an ideal $\mathfrak p \subset R$, and call them an L-pair (just for brevity) if $\mathfrak p$-adic completion of any projective module is again projective (as R-module); and L-...
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Macdonald's notes on Kac Moody algebras

Macdonald had given some lectures on Kac-Moody algebras in 1983. The notes are typed here by Arun Ram. However, the website seems to be old and the notes are somewhat not readable because of the ...
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Moduli of finite-dimensional algebras

Let $n\geq 1$ be an integer. There is an obvious family of $n$-dimensional unital algebras parametrized by $\mathbb{C}^{n(n-1)^2}$ such that any $n$-dimensional unital algebra is isomorphic to at ...
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Question about basis of $\text{Der}_{k}(k[X])$

Let $k[X] = k[x_1,\ldots, x_n]$ be the polynomial ring over a field of characteristic zero. Assume that $(D_1,\ldots, D_n)$ is a $k[X]$-basis of $\text{Der}_k(k[X])$. Suppose that the vector space $\...
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Polynomial objects in any concrete category

EDIT: The original question had a trivial answer: it's just a coproduct. New question below New Question: As shown below, in the category of commutative unital rings, the coproduct of a ring $R$ with $...
Chetan Vuppulury's user avatar
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Is the average associator over a finite subloop of octonions necessarily zero?

For any three octonions $a,b,c$, their associator is defined as \begin{equation*} [a,b,c]=a(bc)-(ab)c \end{equation*} and measures their non-associativity so to speak. Now suppose that $L$ is a finite ...
Bob's user avatar
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The Jacobson radical as a bimodule

Let $A$ be a finite dimensional algebra with Jacobson radical $J$. Question 1: In case $A$ is a Nakayama algebra with a linear quiver corresponding to a Dyck path $D$ (via its Auslander-Reiten ...
Mare's user avatar
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Cohomology and higher structures

Classically, cohomologies of Lie groups/algebras parametrize extensions. To be precise, given an linear $G$-action on $M$, there is an bijection between $H^2(G;M)$ and the set of extension $E$ of $G$ ...
Student's user avatar
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Frobenius algebras of small dimensions

In Classification of commutative Frobenius algebras , Jeremy Rickard showed that there are infinitely many commutative (local without loss of generality) Frobenius algebras of vector space dimension ...
Mare's user avatar
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Prime/irreducible elements in certain (integral) ring extensions

The answer to this question says the following: Let $R$ be a finitely generated $k$-algebra, where $k$ is a field. If $p \in R$ is a prime element, then $p$ is a prime element in $\tilde{R}$, the ...
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Generalization of semi-hereditarity

Let $R$ be a ring. A left $R$-module $K$ is called an $N$-th kernel if there are projective left $R$-modules $P_1, \ldots P_N$ and a short exact sequence $$ 0\rightarrow K \rightarrow P_N \rightarrow \...
nikola karabatic's user avatar
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Other kinds of equivalence relations on the set of idempotents of a Banach or $C^*$-algebra or a ring (Can we get a new kind of K-theory?)

The standard equivalent relations on idempotents of a $C^*$ algebra or a Banach algebra are Murray von Neumann, similarity and homotopy equivalent. In this post we consider two other kinds of ...
Ali Taghavi's user avatar
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Division in the universal enveloping algebra

Let $\mathfrak g$ be a (semisimple) Lie algebra, $\mathfrak b\subset \mathfrak g$ a Borel and $\mathfrak n = [\mathfrak b,\mathfrak b]$. Then I am interested in solving certain division problems in $U(...
Rik Voorhaar's user avatar
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Differential graded Lie algebra over an ordinary Lie algebra

Given a dg (differential graded) Lie algebra $L$ and an ordinary Lie algebra $\mathfrak{g}$, is there written somewhere a formal definition of $L$ as a dg Lie algebra over $\mathfrak{g}$?
Jim Stasheff's user avatar
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Mysterious identity in cosimplicial $R$-module with Lie brackets

I have a cosimplicial $R$-module $\mathscr{A}:=(A_n)_{n\ge 0}$ and on each $A_n$ a Lie bracket $[-,-]_n:A_n\otimes A_n\to A_n$. Denote the cofaces by $d_i:A_n\to A_{n+1}$ and the codegeneracies by $...
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Cyclic relation algebra

A relation algebra $\mathbf{R}$ is a structure $\langle |\mathbf{R}|, \vee, \neg, \circ, I, (-)^{op} \rangle$ such that: $\langle |\mathbf{R}|, \vee, \neg \rangle$ is a Boolean algebra, $\langle |\...
Michal R. Przybylek's user avatar
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Do comodules form an exact category?

Let $R$ be a commutative ring, $C$ a coalgebra over $R$. I am asking about the category of $C$-comodules $C$-Comod. It is clear that if $C$ is a flat $R$-module, then $C$-Comod is abelian. Hence, is ...
Bugs Bunny's user avatar
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Contractible Banach algebras

A Banach algebra $A$ is contractible if $H^1(A, X)=0$ for all Banach $A$-bimodules $X$. Now to my question Let $A$ be Banach algebra and $I$ be closed ideal of $A$. If $I$ and $A/I$ are both ...
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Number of ideals in an algebra

Let $R_{n,m}^q$ be the finite dimensional algebra $K\langle x_1,...,x_n\rangle/J^m$, where the field $K$ has $q$ elements and $K\langle x_1,...,x_n\rangle$ is the non-commutative polynomial ring with ...
Mare's user avatar
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A presentation for a subalgebra

Let $K$ be a field, and let $I=(g_1,\ldots, g_r)$ be an ideal in $A:=K[X_1,\ldots ,X_n]$. Let $\{f_1,\ldots f_m\}$ be a subset of $A$, and let $B$ be the $K$-subalgebra of $A$ generated by $f_1,\...
Ehud Meir's user avatar
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Injective resolution of the ring of entire functions

Let $R$ be the ring of entire functions on $\mathbb{C}$. I heard that the concrete value of the global dimension of the ring depends on continuum hypothesis. I would think that the injective dimension ...
Mare's user avatar
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Recovering the bimodule from the trivial extension

Given a ring $S$ with a non-zero $S$-bimodule $M$, the trivial extension of $(S,M)$ is defined as the ring $R:=T_M(S)$ with $R= S \oplus M$ with multiplication $(s,m)(s',m')=(s s', sm' +m s')$. We ...
Mare's user avatar
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Does linear independence imply algebraic independence for partitioned homogeneous polynomials?

Define a partitioned homogeneous polynomial of degree $d$ to be a polynomial in $$\mathbb Z[x_{11},\dots,x_{1n},\dots,x_{d1},\dots,x_{dn}]$$ with monomials from entries in (polynomials that are $d$-...
Turbo's user avatar
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A relation between $Spec((1+I)^{-1}R)$ and $Spec(R/J)$

Let $R$ be a commutative ring with identity and let $I$ and $J$ be two finitely generated ideals of $R$. Clearly $1+I:=\{1+i:i\in I\}$ is a multiplicative closed subset of $R$. We can consider the ...
Bruce's user avatar
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How to formulate supercommutativity in a characteristic free way?

I would never dare posting this here, but the question https://math.stackexchange.com/q/3019853/214353 on math.SE did not receive any feedback (except for 13 views and one upvote) since November 30, ...
მამუკა ჯიბლაძე's user avatar
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Conjugacy class representatives for the automorphism group of a finite abelian group

Given a finite abelian group $A$, I'd like a list of conjugacy class representatives for its automorphism group ${\rm Aut}(A)$. In fact, it's not important that I have exactly one representative from ...
Matt Ollis's user avatar
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418 views

Quaternion algebras in characteristic 2

Let $k$ be a field and let $Q$ be a quaternion algebra over $k$. It is well known that, if $\mathrm{char}\,k\neq 2$, one can define $Q$ as the $k$-algebra of dimension $4$ generated by elements $x,y$ ...
Caligula's user avatar
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Closing Subsets Under Operations

My question is about closing sets under operations. First, I need a definition: Definition: Let $A$ be a set and take a function $f : A^n \rightarrow A$ for $n \in \mathbb{N}_{\geq 0}$. For a set $S$,...
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tensor products of noetherian domains

Under what conditions is the tensor product of two non-commutative Noetherian domains also a Noetherian domain? To be more precise about the problem, I am looking at rings of fractions on such tensor ...
Edwin Beggs's user avatar
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Question on $n$-torsionless modules

Let $A$ be a finite dimensional algebra. Recall that a module $M$ is called $n$-torsionfree in case $Ext_A^i(D(A),\tau(M))=0$ for all $i=1,...,n$ when $\tau$ denotes the Auslander-Reiten translate. ...
Mare's user avatar
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Sextic resolvent rings of quintic rings

In Higher composition laws IV: The parametrization of quintic rings M. Bhargava gave an explicit parametrization of quintic rings by quadruples of $5\times5$ skew-symmetric matrices. His proof hinges ...
Stanley Yao Xiao's user avatar
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Injective dimension is infinite?

Let $A$ be a non-selfinjective finite dimensional algebra and $M$ a nonprojective module with $Ext^{i}(M,A)=0$ for all $i \geq 1$. It is easy to see that $M$ has infinite projective dimension. Does $M$...
Mare's user avatar
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How can one prove that the algebra of smooth functions is semisimple?

I have read in some differential geometry works that the ring of smooth functions $C^{\infty}(U)$ is a semi-simple ring, for $U\subseteq\mathbb{R}^n$ an open set; right now I can cite a remark ...
mathbekunkus's user avatar
4 votes
1 answer
350 views

Values attained by the coheight of $(H \setminus H^\times)^k$ as a function of $H$ and $k$

Edit (Apr 24, 2017). I'm updating this post in the light of the latest developments of a related thread. Let $H$ be a multiplicatively written, commutative monoid, and set $M := H \setminus H^\times$,...
Salvo Tringali's user avatar
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95 views

$\lambda$-Decomposition for Connes' Cyclic Complex

Let $k$ be a field of characteristic zero, and $A$ be a commutative unital $k$-algebra. Then the cyclic homology of $A$ has a $\lambda$-decomposition: $$HC_{n}(A)=HC_{n}^{(1)}(A)\oplus \cdots \oplus ...
Yining Zhang's user avatar
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178 views

ring structure of $KK_*(A,A)$ for a separable $C^*$-algebra $A$

Motivation: For a topological space $X$ one can consider under certain circumstances the cohomology ring of suitable cohomology theories, for example: 1) The cohomology ring $H^*(X;R)=\oplus_{i\ge ...
Sabrina Gemsa's user avatar
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Existence of infinitely many pairwise non-associate atoms in a ring of polynomials in $k$ variables over a Dedekind-finite unital ring

The following comes as a by-product of a more abstract result, and I'm essentially looking for a reference to it (or to something more general than it). Corollary. Let $R$ be a non-trivial Dedekind-...
Salvo Tringali's user avatar
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0 answers
293 views

Does the tensor algebra $T(V)$ of $V$ isomorphic to the symmetric algebra of the free Lie algebra over $V$?

Let $V$ be a finite dimensional vector space. Let $T(V)$ be the tensor algebra over $V$. Do we have $T(V) \cong S(Lie(V))$ as a graded vector space? Here $S(Lie(V))$ is the symmetric algebra of the ...
Jianrong Li's user avatar
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Inducing surjections on $GL_n(-)$?

Suppose $A,\,B$ are (possibly noncommutative) rings, and $GL_n(-)$ is the group of invertible $n\times n$ matrices over a given ring. Suppose $f:A\to B$ is surjective, does it necessarily follow that $...
BillScroggs's user avatar
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74 views

self-cogenerator rings

Let $\mathbb{U}$ be a non-empty set (class) of objects of a category $C$. An object $B$ in $C$ is said to be cogenerated by $\mathbb{U}$ or $\mathbb{U}$-cogenerated if, for every pair of distinct ...
e.r's user avatar
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Generators of the symmetric square of the group ring of an abelian group

Let $A$ be an abelian group and $R=\mathbb{Z}[A]$- its group ring. Denote by $I$ an ideal of $R$ given by a kernel of the map $R\longrightarrow \mathbb{Z} \oplus A,$ sending $[r]$ to $(1,r)$. Next, ...
Daniil Rudenko's user avatar
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0 answers
390 views

Reference for classification of positive involutions

An involution on a finite dimensional algebra $A$ over $\mathbb{Q}$ is an involutive anti-automorphism of $A$. If $\sigma$ is an involution on $A$, we say that $\sigma$ is positive if $\mathrm{Tr}_{A/\...
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