0
votes
1answer
14 views
Vector field pull back from embedding
Let $M$ and $N$ be finite dimensional smooth manifolds.
A smooth map $f: M \to N$ is an embedding if and only if there is an
open neighborhood $U$ of $f(M)$ in $N$ and a smooth ma …
4
votes
1answer
125 views
Reference request: affine transforms + circle inversion?
This problem cropped up in the context of scale-insensitive methods for generating random variables.
Let $X=R^n \cup \{\infty\}$. Suppose we consider a set of transforms $\cal{T} …
7
votes
1answer
108 views
Is this combination of generalized polygamma and dilogarithm actually zero? $\Im\;\psi^{(-2)}(1+i)+\frac1{4\pi}\text{Li}_2(e^{-2\pi})-\log\sqrt{2\pi}+\frac{5\pi}{24}+\frac12$
I encountered this quantity in my calculations and tried to simplify it. Approximate numeric calculations suggested it could be zero (more precisely, it is certainly less than $10^ …
0
votes
1answer
21 views
The sufficient condition of the Neumann problem
How can we prove that if $\int_U{f}=0$,then the homogeneous Neumann problem $\Delta u=f$on U,and $\frac{\partial u}{\partial n}=0$ on $\partial U$ has a weak solution in $H^1(U)$? …
0
votes
0answers
8 views
Reference request: construction of Steenrod operations for an odd p
Where in literature can one find a construction of Steenrod
reduced powers (for an odd $p$) that
(1) works for the singular cohomology of arbitrary topological spaces
(or, more …
2
votes
1answer
20 views
Is the equivalence between a $\Sigma^0_1$ and a $\Pi^0_1$ formula defining the same recursive set provable in a sufficiently strong arithmetic ?
Let $A$ be a recursive set. $A$ is recursively enumerable, so $A$ may be defined by a $\Sigma^0_1$ formula, i.e. by $\exists \overrightarrow{a} \phi (\overrightarrow{a}, n)$, where …
2
votes
1answer
120 views
Reference request: Minimal Axiomatizations of PA over (+,x,<=).
Many years ago, when I was still a high school student, I came up with a certain first-order axiomatization of PA over the signature (+, x, ≤). Out of nostalgia, I've decided t …
0
votes
0answers
15 views
Is there an “accepted” jamming limit for hard spheres placed in the unit cube by random sequential adsorption?
I have a unit cube, and operating in the continuum limit (i.e. not on a lattice), I sequentially place spheres of some radius $r$ inside the cube until a filled volume "jamming lim …
3
votes
1answer
39 views
Well-Ordering theorem of cardinal$\kappa$
I've heard from others about the WO($\kappa$) as a counterpart of AC($\kappa$), but I cannot find a suitable way to express it in ZF since "every set of cardnality $\kappa$ can be …
3
votes
1answer
95 views
Basics of minimal Elliptic Surfaces [following Beauville]
I am reading Beauville's chapter IX on Elliptic surfaces.
Let $S$ be a minimal elliptic surface with $\kappa=1$ and $p:S\rightarrow C$ be the elliptic fibration.
We know $K^2=0$ …
0
votes
1answer
57 views
Odd-order groups with homocyclic sylow subgroups
We say that $G$ is a homocyclic group, if it is direct product of isomorphic cyclic groups.
Is there any classification of finite odd-order groups which all their Sylow subgroups a …
5
votes
6answers
401 views
Sequences equidistributed modulo 1
Let $\alpha$ be any positive irrational and $\beta$ be any positive real. We have the following results.
H. Weyl (1909): The fractional part of the sequence $\alpha n$ is equidist …
9
votes
3answers
444 views
Good uses of Siegel zeros?
The short version of my question goes: What is known to follow from the existence of Siegel zeros?
A longer version to give an idea of what I have in mind: The "expectional zeros" …
0
votes
1answer
43 views
Free resolution for Lie algebras (reference)
What is a reference for the subject of "free resolutions for Lie algebras"?
Does the term "standard resolutions" means "free resolutions"?
What is a "bar resolution"?
Is there o …
4
votes
0answers
41 views
Why do rigid spaces have “not enough points”?
In Brian Conrad's notes
here for the 2007 Arizona winter school, bottom of p18, he says that there is an affinoid rigid-analytic space and a sheaf of abelian groups on it equipped …

