5
votes
3answers
249 views
A question about Mitchell/Steel Fine Structure and Iteration Trees
In chapter 8 of Mitchell's and Steel's FSIT, they prove a central fine structural result, which basically states that if $\mathcal{M}$ is 1-small, $k$-sound, $k$-iterable premouse …
4
votes
1answer
185 views
Models of Determinacy
Today we have that $L(\mathbb{R}) \models AD$ (assuming there are $\omega$ many Woodin cardinals and a measurable above them all). I was wondering what other models of $AD$ might l …
4
votes
1answer
120 views
$\omega$-small and properly small premice.
Let $\mathcal M$ be a premouse.
$\mathcal M$ is said to be $\omega$-small if and only if whenever we have that $\kappa=crit(E)$ for some extender $E$ on the sequence of $\mathcal M …
12
votes
1answer
607 views
Devlin’s “Constructibility” as a resource
It is fairly well-known among set-theorists that Keith Devlin's 1984 book "Constructibility" has flaws in its initial development of fine structure theory. (See Lee Stanley's revie …
9
votes
1answer
225 views
Do indiscernibility embeddings exist for an initial segment of an inner model of many measurable cardinals?
Background
I am interested in elementary embeddings from a model of set theory into itself. One way of producing such elementary embeddings is when the model is generated by indis …
7
votes
1answer
323 views
Why “adding” a single extender cannot give an L-like inner model for say, a strong cardinal?
The constructible universe $L$ is too thin for large cardinals greater than measurable. To build $L$-like inner models for large cardinal, it is natural to think about "adding" the …
3
votes
1answer
307 views
The Covering Lemma for L[U]
Hi,
The covering lemma for L[U] (minimal k-model) is stated in Mitchel's handbook chapter:
"Assuming zero-dagger does not exist then covering holds for L[U] or there is a sequenc …
5
votes
1answer
338 views
Characterizing elementary embeddings of $L$ and $L_\alpha$ under 0#
Suppose 0# exists.
It is clear that every order preserving map from the indiscernibles to the indiscernibles gives an elementary embedding from $L$ to $L$. Furthermore, following …

