Questions tagged [homological-algebra]

(Co)chain complexes, abelian Categories, (pre)sheaves, (co)homology in various (possibly highly generalized) settings, spectra, derived functors, resolutions, spectral sequences, homotopy categories. Chain complexes in an abelian category form the heart of homological algebra.

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Invertible bimodules and projectivity

Let $A$ be a noncommutative algebra over a field, say $\mathbb{C}$ or $\mathbb{R}$, and let $L$ be a bimodule over $A$. If $L$ is invertible, that is, if the dual right $A$-module $L^*$ satisfies $$ L^...
Rodrigo Alfonso de la Paz's user avatar
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1 answer
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Postprojective components of quiver algebras

Let $A=kQ/I$ be a quiver algebra with acyclic quiver $Q$. An indecomposable module $M$ is called postprojective in case $M \cong \tau^{-1}(P)$ for an indecomposble projective module $P$. A component ...
Mare's user avatar
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1 answer
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Residual Finiteness for 3-Manifolds Hempel

Hempel, in his 1987 article "Residual Finiteness for 3-Manifolds", shows that if $M$ is a compact Haken 3-manifold, then $\pi_1(M)$ is residually finite. In the proof he starts by reducing the case to ...
aceituna's user avatar
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2 answers
280 views

Is Hilbert basis theorem true for positive graded ring?

Let $R=\oplus_{I\geq 0}R_i$ be a positive graded ring(maybe not commutative), where $R_0$ is a commutative Noetherian ring. If $R$ is finite generated $R_0$-algebra, is $R$ Noetherian? In here, Is ...
Jian's user avatar
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236 views

Is being derived equivalent independent of the field?

Let $Q_1, Q_2$ be (connected) acyclic quivers and $I_1, I_2$ admissible ideals (in which the relations have only coefficients 1 or -1). Let $K$ and $F$ be two fields. Question 1: Is $KQ_1/I_1$ ...
Mare's user avatar
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76 views

Singular chain complex of balanced products

Let $\pi\subseteq\Sigma_r$ and $V$ be a right $\pi$-space. We may assume that $V$ is free, if necessary. Consider the morphism of singular chain complexes (over a fixed commutative ring) $$f:C_*(V) \...
FKranhold's user avatar
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Regarding linear splitting of lie algebra morphism and their CE complexes

The main question here is to ask if anyone has ever seen/researched the map $\alpha$ below and get a reference regarding it. Also, if anyone tells me the equivalent conditions to $\alpha=0$, I would ...
sock's user avatar
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6 votes
1 answer
206 views

Derived invariant for Gorenstein algebras?

Let $A$ be a finite dimensional algebra with simple modules $S_i$ and projective indecomposable modules $P_l$ and global dimension $g< \infty$ (and $n$ is the number of simple modules). I noted ...
Mare's user avatar
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Augmented algebras over semisimple ring

Let $A$ be a non-negatively graded algebra such that $A_0 = k$. We say that $A$ is Koszul if $k$ has a projective resolution by projective modules such that the i-th piece is generated in degree $i$. ...
Federico Barbacovi's user avatar
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Global dimension 2 Nakayama algebras , 321-avoiding permutations and Fibonacci combinatorics

A $n$-LNakayama algebra (for $n \geq 2$) is a list $[c_0,c_1,...,c_{n-1}]$ with $c_{n-1}=1$, $c_i \geq 2$ for $i \neq n-1$ and $c_i -1 \leq c_{i+1}$ for all $i$. They are in bijection with Dyck paths, ...
Mare's user avatar
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2 votes
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Projective dimension of the functions with compact support

Let $X$ be a locally compact Hausdorff space. And $C(X)$ the ring of all continous real-valued functions and $J(X)$ the ideal of such functions with compact support. It is known that $X$ is ...
Mare's user avatar
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14 votes
3 answers
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Is $C^{\infty}(\mathbb{R}^{m+n})$ a flat module over $C^{\infty}(\mathbb{R}^{m})$?

For $m>0$ we consider the ring $C^{\infty}(\mathbb{R}^{m})$ of smooth functions on $\mathbb{R}^{m}$. For $n>0$ we consider the projection $\mathbb{R}^{m+n}\to \mathbb{R}^{m}$ hence $C^{\infty}(\...
Zhaoting Wei's user avatar
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171 views

Quiver algebras with finite global dimension

Given a fixed connected quiver $Q$. Are there only finitely many quiver algebra $KQ/I$ (I an admissible ideal) up to isomorphism which have finite representation type and finite global dimension?
Mare's user avatar
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Ordered sequence of elements of poset relevant to some filtration -- highest weight category

Let $\mathcal{C}$ be a highest-weight category with $\Lambda$ as a interval-finite poset -- I'm using a definition of the highest-weight category given by Cline, Parshall and Scott and it is presented ...
jpatrick's user avatar
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Characterisation of algebras with Euler trivial modules

Let $A$ be an algebra of finite global dimension. The Euler form on $A$ for an indecomposable module $M$ is defined as $\psi(M)=\sum\limits_{k=0}^{\infty}{(-1)^k dim( \operatorname{Ext}_A^k(M,M)) }$. ...
Mare's user avatar
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8 votes
0 answers
315 views

Bringing cohomology recipes from algebra to topology?

In algebra, cohomology theories are often defined very roughly like this. Start with a scheme $X$ you want to study. Form a category-with-extra-structure (a site) $\mathcal{C}$ whose objects are, ...
John Greenwood's user avatar
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0 answers
108 views

When is a chain complex induced up to quasiisomorphism

I have a field extension $F/F'$ and an algebra $L'$ over $F'$. Let $L$ be the induced $F$-algebra $F\otimes_{F'}L'$ and $C_*$ a chain complex over $L$. Is there a good way to decide whether $C_*$ is ...
HenrikRüping's user avatar
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538 views

A lemma on a sequence of three morphisms

Few months ago, I proved that when there is three morphisms of modules over a commutative ring with zero composition, i.e., a sequence $$A \xrightarrow{\alpha} B \xrightarrow{\beta} C \xrightarrow{\...
HyJu's user avatar
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1 answer
310 views

Indecomposable objects in bounded derived category of $\mathbb C[x]/x^2$-mod

We know for any principal ideal domain, objects in the bounded derived category are all formal hence we can classify those objects with finitely generated cohomology using structure theorem for ...
sawdada's user avatar
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5 votes
0 answers
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On algebras where all indecomposables have no selfextensions

Let $A$ be a finite dimensional algebra (we can assume it is a connected quiver algebra). Call $A$ extfree in case for every indecomposable $A$-module $M$ we have $\operatorname{Ext}_A^i(M,M)=0$ for ...
Mare's user avatar
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2 votes
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Bimodule resolutions

I have asked this question on Mathematics Stack exachange but didn't get any reply yet. So, I am asking it here. Let A be a finite-dimensional algebra. Let M be a left A-module and N be a right A-...
Sam's user avatar
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612 views

"Differential graded homological algebra" by Avramov, Foxby and Halperin

I am looking for "Differential graded homological algebra" by L. Avramov, H. Foxby, and S. Halperin, which is widely cited as a preprint o as a manuscript, e.g. https://scholar.google.com/scholar?q=L....
Christa Wolf's user avatar
1 vote
0 answers
73 views

Simpicial resolution in Cotangent Complex

I am reading Cotangent complex from Loday's book Cyclic Homology. My doubt is related to the simplicial resolution of $k$- algebra $A$ which is used in the definition of cotangent complex.. Let me ...
Sunny's user avatar
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0 answers
160 views

multiplication in spectral sequence

I am trying to understand this paper. Let $M$ be a compact Kaehler manifold of dimension $n$, $X$ is a holomorphic vector field, $i_X$ the contraction operator, i.e. for $\alpha$ a $p$-form, then $i_X(...
Anh Dũng Lê's user avatar
4 votes
1 answer
156 views

injective hulls in mixed characteristic

Let $R=\underleftarrow\lim (R/\mathfrak m^i)$ be a complete local ring, with residue field $k=R/\mathfrak m$, and let's assume that $R$ is Noetherian. If $R$ is a $k$-algebra, then I believe that ...
André Henriques's user avatar
6 votes
1 answer
202 views

When is the Jacobson radical reflexive?

Let algebras be Artin algebras. It is well known that a an algebra has global dimension at most one if and only if the Jacobson radical is projective. As reflexive is a natural generalisation of ...
Mare's user avatar
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3 votes
0 answers
327 views

Fibered category vs indexed category

In Benabou's paper Fibered categories and the foundations of naive category theory, it is mentioned (end of page 31) that 'an indexed category is just a presentation of a fibered category.' It seems ...
Hang's user avatar
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3 votes
0 answers
200 views

Yoneda extension and splittings

Let $X$ be a non-singular algebraic variety and $F$ be a coherent sheaf defined over $X$. Suppose that we have a locally free resolution $$0 \to L_n \xrightarrow{f_n} L_{n-1} \to ... \to L_0 \to F \to ...
Ron's user avatar
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5 votes
1 answer
310 views

Resolutions of $\mathbb{Z}_{(p)}$ as $\mathbb{Z}$-module

Are there any interesting canonical (maybe unbounded) projective resolutions of $\mathbb{Z}_{(p)}$ over $\mathbb{Z}$, for instance by tensoring together all the $\mathbb{Z}[x] \stackrel{qx-1}\to \...
Oren Ben-Bassat's user avatar
3 votes
1 answer
137 views

Artinian Tor modules (Reference request)

I am looking for a reference for the following basic fact: Let $R$ be a noetherian ring, let $M$ be an artinian $R$-module, let $N$ be a finitely generated $R$-module, and let $i\in\mathbb{N}$. ...
Fred Rohrer's user avatar
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7 votes
2 answers
618 views

Concrete examples of Freyd-Mitchell embedding

I originally posted this on math.SE (https://math.stackexchange.com/questions/3438528/concrete-examples-of-freyd-mitchell-embedding) but since it's been a few days I figured I would crosspost it here. ...
Spencer Dembner's user avatar
12 votes
0 answers
379 views

Which abelian categories have homological dimension 1?

In this MSRI lecture Geometry of Quiver Varieties I, Victor Ginzburg describes all abelian categories of homological dimension $1$ as being either a category of representations $\mathrm{Rep}_\mathbf{...
Mike Pierce's user avatar
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2 votes
1 answer
213 views

Computation of $\mathcal{Tor}_i^{O_X}(O_{Z},O_{Z})$ for non-complete intersection $Z$ in $X$

Let $Z \hookrightarrow X$ be a closed subvariety of a smooth projective variety. How do we compute $\mathcal{Tor}_i^{O_X}(O_{Z},O_{Z})$ $(i>0)$ as coherent sheaves on $Z$ where $Z$ is not of ...
sawdada's user avatar
  • 6,158
11 votes
1 answer
256 views

What are the projective dimensions of big fraction fields?

Let $A$ be an integral domain, $B$ is its fraction field. Can the projective dimension of the $A$-module $B$ be greater than $1$? This surely cannot happen if the spectrum of $A$ is countable (since ...
Mikhail Bondarko's user avatar
2 votes
1 answer
382 views

An action of the symmetric group $S_n$ on group cohomology $H^n(G, A)$ of abelian groups

Let $H$, $A$ be discrete abelian groups, and for simplicity suppose $A$ is given the trivial $H$-action. When considering the second cohomology group $H^2(H,A)$, it is natural to talk about the ...
Freddie Manners's user avatar
11 votes
1 answer
2k views

Why does K-theory need schemes to be Noetherian?

The definition of K-theory of a scheme $X$ is defined as $G_i(X):=K_i(\mathrm{Coh}(X))$ or $K_i(X):=K_i(\mathrm{Vec}(X))$. But usually the schemes are required to be (at least locally) Noetherian, and ...
Li Guanyu's user avatar
  • 439
1 vote
1 answer
128 views

'Quotient' of indexed categories and pushforward congruence relations

If $R\subset C$ is a vector subspace of $C$, and $F: C \to D$ is a linear map, then we have a natural linear map $C/R\to D/F(R)$. I was wondering if this can be also generalized to categorical ...
Hang's user avatar
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2 votes
0 answers
166 views

Geometric meaning of Koszul modules

Assume $C$ is a smooth projective curve and $L$ is a line bundle on it. We say $L$ is $p$-very ample if for any effective divisor $D$ of degree $p+1$, the evaluation map $H^0(C,L)\to H^0(C,L\otimes\...
Li Li's user avatar
  • 393
2 votes
0 answers
104 views

Tate cohomology for group algebras

Let $A=kG$ be a group algebra with a finite group $G$ and a field $k$. Let $T^i(M,N)= \underline{Hom_A}(\Omega^i(M),N)$ be the $i$-th Tate cohomology group. Note $T^i(M,N)= Ext_A^i(M,N)$ in case $i \...
Mare's user avatar
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9 votes
1 answer
183 views

Betti sequence of finite dimensional commutative algebras

Given a finite dimensional commutative local $K$-algebra $A$ for a field $K$. Associated to $A$ is its dimension $d_A$ and the Betti-sequence $c_i=dim(Ext_A^i(S,S))$ where $S$ is the unique simple $A$-...
Mare's user avatar
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1 vote
0 answers
164 views

Translate a construction into categorical languages

Let $\mathscr C$ be a category whose objects are sets. Let $\mathscr V$ be another category. It seems that the usual composition in $\mathscr V$ can be somehow 'twisted' by $\mathscr C$. I notice that ...
Hang's user avatar
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10 votes
1 answer
316 views

Commutative algebras with modules of small complexity

Let $A$ be a finite dimensional commutative algebra. We can assume that it is local. Question: Which such $A$ have the property that every finite dimensional $A$-module has complexity at most 1? (...
Mare's user avatar
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5 votes
1 answer
564 views

Functoriality of filtered spectral sequences

What is the appropriate functoriality statement of a filtered chain map between filtered spectral sequences? Suppose that we have two filtered chain complexes $C,C'$ and a filtered chain map $f\colon ...
Onkar Singh Gujral's user avatar
6 votes
1 answer
163 views

Relative Ext of Avramov-Martsinkovsky as a derived Hom

Avramov-Martsinkovsky (http://mathserver.neu.edu/~martsinkovsky/Relative.pdf) have defined an exotic version of Ext between two modules over (for simplicity) Gorenstein rings. The basic idea of their ...
Daniel Pomerleano's user avatar
8 votes
1 answer
1k views

Geometric intuition behind this chain homotopy

My question has to do with the chain homotopy that appears in Lee's Introduction to Topological Manifols and Rotman's Introduction to Algebraic Topology proofs that the inclusion $$C_\bullet^\mathcal{...
Akerbeltz's user avatar
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3 votes
1 answer
543 views

Questions about Deligne's tensor product of abelian categories

Let $A$ and $B$ be abelian categories, then $A \times B$ is an abelian category. Also denote $Ab$ to be the category of abelian groups or any abelian category. If want to study a bi-additive (also ...
wkf's user avatar
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3 votes
0 answers
92 views

On NCR for finite dimensional algebras

Let $A$ be a finite dimensional algebra. A NCR of an algebra $A$ is a faithful module $M$ such that $End_A(M)$ has finite global dimension. Call a faithful module PNCR (=pseudo-NCR) in case $End_A(M)$ ...
Mare's user avatar
  • 26k
11 votes
1 answer
1k views

Derived categories and classical theorems in homological algebra

So far I have studied fundamental part of derived category theory, for example, the existence of derived functors, the "composition of derived functors", and so on. Now I came up with some questions ...
k.j.'s user avatar
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6 votes
1 answer
379 views

Tor functor and invertible elements

Let $A$ be a commutative ring, $a \subset A$ be an ideal. For $A$-module $M$ let $S \subset A$ be the set of elements, which are invertible in $M$, so $M$ is actually a $S^{-1}A$-module. It is not ...
Boris Bilich's user avatar
2 votes
1 answer
295 views

Gaps in the projective dimensions of simple modules

Let $A$ be a finite dimensional algebra with finite global dimension $g$ and $n$ simple modules. Let $d_1<d_2<...<d_r$ be the sequence of projective dimension of simple $A$-modules in ...
Mare's user avatar
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