3
votes
2answers
395 views
Skew fields inside quaternion division algebras
Suppose that $Q$ is a quaternion division algebra with center $k$, where $k$ is an arbitrary commutative field (let's say with $\operatorname{char}(k) \neq 2$ if necessary). Assume …
1
vote
2answers
215 views
What structure supports division to a unique quotient and remainder?
This has been bugging me for a while.
According to https://en.wikipedia.org/wiki/Euclidean_division, if I divide integer $a$ by integer $b$, I get unique $t$, $r$ such that $a = t …
2
votes
1answer
125 views
equivalence of maximal fields in division algebras
Let D be a division algebra over F, E its maximal field. Is it true that:
1) all such fields are equivalent over F?
2) all such fields are conjugate by inner automorphisms of D?
11
votes
0answers
343 views
finite dimensional real division algebras
A celebrated theorem of Milnor and Kervaire asserts that any finite dimensional division algebra over the real numbers has dimension 1,2,4 or 8. This result is established using me …
2
votes
1answer
493 views
Central division and quaternion algebras
I would like to know if there are some central-simple algebras $D_1$, $D_2$ and $D_3$ over a field $k$ satisfying the following properties :
$ind(D_1)=exp(D_1)=4$ ($ind$ is the S …
12
votes
3answers
903 views
How to distinguish division algebras from matrix algebras?
Suppose $D$ is an explicitly given rank 9 central simple algebra over ${\mathbb Q}$ (or a number field). For example it could be specified by two cubic subfields ${\mathbb Q}(a), { …
-3
votes
4answers
1k views
Why don’t quaternions have an overall phase? [closed]
The product of a quaternion multiplied by a real number is a quaternion, but the product of a quaternion multiplied by a complex number is not in general a quaternion. Why are the …
16
votes
3answers
874 views
Infinite-dimensional normed division algebras
Let's say a normed division algebra is a real vector space $A$ equipped with a bilinear product, an element $1$ such that $1a = a = a1$, and a norm obeying $|ab| = |a| |b|$.
The …
11
votes
4answers
795 views
Dimension of central simple algebra over a global field “built using class field theory”.
If $F$ is a global field then a standard exact sequence relating the Brauer groups of $F$ and its completions is the following:
$$0\to Br(F)\to\oplus_v Br(F_v)\to\mathbf{Q}/\mathb …
1
vote
0answers
163 views
(Non-)existence of skew fields satisfying a SGPI (=skew generalized polynomial identity)
Let $K$ be a skew-field, infinite dimensional over its center $F$.
From Kaplansky's PI-theorem it then follows that $K$ cannot satisfy a polynomial identity (the theorem says tha …
0
votes
1answer
541 views
identity for matrices whose determinant is 1.
For any matrices $A$,$B$ in $SL(2,\mathbb{C})$, let $M(A,B)$ be the 4 by 4 matrix whose columns are matrices $I$,$A$,$B$,$AB$. Then it is not hard to verify that $det M(A,B)= 2- tr …
4
votes
2answers
574 views
Splitting of a division algebra with an involution of second kind
Let $k$ be a field, $K/k$ a separable quadratic extension,
and $D/K$ a central division algebra of dimension $r^2$ over $K$
with an involution $\sigma$ of second kind
(i.e. $\sigma …
11
votes
2answers
612 views
units in distinct division algebras over number fields---are they definitely not isomorphic as abstract groups?
This is really an irrelevant question in the sense that the answer isn't remotely "logically crucial for the Langlands programme" or whatever---it's just something that occurred to …
2
votes
1answer
529 views
Maximal subfield inside a central division algebra
D is a central division algebra over F. We know that we can always find a maximal subfield K inside D such that K/F is separable. I want to know can we always make it Galois?

