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I'm interested in showing the existence of a generating function. Explicitly:

Suppose $\Lambda\subset T^*M\times T^*M$ is a Lagrangian submanifold. Consider the projection $\pi:(x_1,\xi_1,x_2,\xi_2)\mapsto(x_1,\xi_2)$. If $\pi|_\Lambda$ is a diffeomorphism, how might I show that there exists a generating function $G(x_1,\xi_2)$ such that $\Lambda=\{(x_1,\frac{\partial{G}}{\partial{\xi_2}},-\frac{\partial{G}}{\partial{x_1}},\xi_2)\}$?

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1 Answer 1

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When $(M_1,\omega_1)$ and $(M_2,\omega_2)$ are symplectic manifolds then we endow $M_1\times M_2$ with the symplectic form $\omega_1\ominus\omega_2:=\pi_1^\ast\omega_1-\pi_2^\ast\omega_2,$ (where $\pi_i:M_1\times M_2\to M_i$ denotes the projection on the $i$-th factor.)

Let $\Lambda$ be an arbitrary Lagrangian submanifold of $M_1\times M_2,\omega_1\ominus\omega_2),$ and $i:\Lambda\to M_1\times M_2$ the inclusion map.
Fixed $p\in\Lambda$, for any primitive $\theta$ of $\omega_1\ominus\omega_2$ in a neighborhood of $p,$ there exists a smooth local function $S$ around $p$ such that $dS=i^\ast\theta.$ (Because of Poincaré Lemma and $0=i^\ast(\omega_1\ominus\omega_2)=i^\ast d\theta=d(i^\ast\theta).$)
Such a function $S$ is called generating function for $\Lambda,$ and, being only locally defined, it depends on the choice of $\theta.$

To be more specific:
In your context $\omega_i=d\xi_i\wedge dx_i$ is the canonical $2$-form on $M_i=\mathbb{R}^{2n},$ for $i=1,2,$ and $\Lambda$ is the image of $i:(u,f(u,v),g(u,v),v)\in\mathbb{R}^{2n}\to(u,v)\in\mathbb{R}^{4n}.$
As remarked above the local generating functions for $\Lambda$ are sensitive to our choice of the local primitive $\theta_i$ of $\omega_i.$

Let us choose $\theta_1=\xi_1 dx_1$ and $\theta_2=-x_2d\xi_2.$
Then the corresponding generating function is determined (up to a constant) by $dS=i^\ast(\theta_1\ominus\theta_2)=fdu+gdv,$ i.e.: $f=\frac{\partial S}{\partial u},\ g=\frac{\partial S}{\partial v}.$

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