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The error begins in line zero: Calculate without fixing a definition of $e^z$. – Martin Brandenburg Mar 17 2012 at 15:09
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 That is not the problem, $e^z=1+z+{1\over 2}z^2 +{1\over 6}z^3+\ldots$ is perfectly well-defined. – Robert Kucharczyk Mar 17 2012 at 15:11
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 The problem is not with defining $e^z$. It's with defining $a^z$ for $a\neq e$. – Steven Landsburg Mar 17 2012 at 15:26
mathoverflow.net/faq#whatnot – Yemon Choi Mar 18 2012 at 19:37
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 There does not seem to be any further need to edit this question. Please let it be. – S. Carnahan♦ Mar 20 2012 at 8:57

closed as off topic by Alain Valette, Kevin Walker, Neil Strickland, Martin Brandenburg, Steven Landsburg Mar 17 2012 at 15:22

1 Answer

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The equality $(e^z)^w = e^{zw}$ does not hold for $z,w \in \mathbb{C}$ in general, so the error lies between lines three and four.

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 To be more precise, the expression $a^b$ for arbitrary complex numbers $a,b$ is not well-defined, but the expression $e^b$ is. – Robert Kucharczyk Mar 17 2012 at 15:13

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