lets say we have the following optimization problem:
min max $|Ax|$ .
s.t. $Hx \leq h$ .
and $x \in {-1,1}$
This is minimax problem that can be cast into an Integer Linear Program using Chebyshev programming
min $t$ .
s.t. $|Ax| \leq t$ .
$Hx \leq h$
and $x \in {-1,1}$
the trivial solution when relaxing this problem to an LP problem is the all zero vector. I am wondering how to avoid this trivial solution. I'm trying a lot to cast the problem in a different way, but I haven't succeeded.


$\delta \in \{0,1\}$. In the LP relaxaton, the binary variable is relaxed thus: $\delta \in [0,1]$. This means that at all integer-feasible points, $x$ is either $-1$ or $1$. – Gilead Mar 10 2012 at 2:11