Take the 2-minute tour ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

Let $\mathcal{H}$ be a separable infinite dimensional Hilbert space. Suppose that $\mathcal{H}_0\subset\mathcal{H}$ which is a dense proper subspace is the range of some bounded linear operator $T$. It is known that there are many bounded linear operator $X$ preserving $\mathcal{H}_0$ invariant.

Now given disjoint dense proper subspace $\mathcal{H}_1$ and $\mathcal{H}_2$ of $\mathcal{H}$. If there are two bounded linear operators $T_1$ and $T_2$ such that $\mathcal{H}_{i}=Ran(T_i)$ and $X \mathcal{H}_i\subset\mathcal{H}_i$, does the bounded operator $X$ need to be the form $\lambda I$ where $\lambda$ is a complex number?

share|improve this question
    
Would you please write your question in understandable English and indicate why you are interested in the question and on what spaces? –  Bill Johnson Mar 6 '12 at 20:16
add comment

2 Answers

Of course, not. One can do a purely geometric construction, but, being a Fourier analyst, I'm tempted to present something involving the Fourier transform, so here goes. Let $T_1$ be the multiplication by $e^{-|x|}$ on the space side and let $T_2$ be the multiplication by $e^{-1/x^2}$ on the Fourier side. Than the ranges are dense and essentially disjoint (If $f$ is in the intersection, then $\hat f$ is an analytic function in a horizontal strip that has a very deep zero at the origin, so it is $0$ identically). However, any convolution with compactly supported $L^1$ kernel preserves both ranges.

share|improve this answer
add comment

Dear Professor Fedja, it is a good hint. Thank you! I am an oeperator algebrast and am trying to solve some problems which involve the Fourier analysis and the operator theory. Would you like to give me your email so that I can contact with you?

share|improve this answer
    
To be honest, I prefer a public discussion. Just post your questions here or on AoPS (the SE forum moves too fast and is too overcrowded with people looking for help with their homeworks to run the discussion there, but AoPS College playground is a nice place if you think that your questions are not OK for MO). –  fedja Mar 21 '12 at 2:49
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.