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Assume, $M$ is a smooth manifold with a measure $\mu$ and let $L^2(M, \mu)$ be a space of all square-integrable functions on $M$.

Recall that $L$ is a hypoelliptic differential operator, if for every $f \in \mathcal{D}(L)$, if $Lf$ is in $C^\infty(M)$ then $f$ is also in $C^\infty(M)$.

Could anyone give a reference to the example when $L$ is hypoelliptic but its adjoint w.r.t to $\mu$ is not hypoelliptic? Could this happen to the Hormander operators, when $L$ is defined as $$ L = \sum_i X_i^2 + X_0 $$ and $\{X_i\}$'s are bracket generating?

I am mostly interested in the case when $\mu$ is induced by the Riemannian metric and $M$ is complete.


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up vote 5 down vote accepted

Hormander's operator $L=X_0+\sum_{1\le j\le k} X_j^2$, where the $X_j$ are real smooth vector fields with the Lie algebra of $\{(X_j)\}_{0\le j\le k}$ generating the tangent space is hypoelliptic as well as its adjoint since the Lie algebra condition does not change by taking adjoints.

On the other hand, $\frac{\partial}{\partial t}+t\Delta_x$ is hypoelliptic whereas its adjoint $-\frac{\partial}{\partial t}+t\Delta_x$ is not hypoelliptic,


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Could you explain why the operators $\frac{\partial}{\partial t} + t \Delta_x$ and $-\frac{\partial}{\partial t} + t \Delta_x$ are hypoelliptic and not, respectively? – Bob Yuncken Jul 22 '15 at 14:13

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