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I've been googling around but I couldn't get to know how to simplify this function without using karnaugh maps.. I can only find answers where only 2 or 3 variables are present in the question. Could anyone help me with this one?

Simplify the Boolean expression E= A!B!C + !A!CD + ABD + BCD by algebraic simplification.

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voting to close because it's not a research-level question – Andreas Blass Jan 9 2012 at 19:43
Ask elsewhere, perhaps on an intro CS forum. With a Karnaugh map I got 3 terms, two of them with two literals each. Gerhard "Ask Me About System Design" Paseman, 2012.01.09 – Gerhard Paseman Jan 9 2012 at 23:23

closed as off topic by Andreas Blass, Joel David Hamkins, Brendan McKay, Bill Johnson, Benjamin Steinberg Jan 10 2012 at 2:45

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