Hi,
How to calculate number of circles in side a square, if we know the side of the square and the circles all are equal size.
Thanks.
Hi, How to calculate number of circles in side a square, if we know the side of the square and the circles all are equal size. Thanks. 

closed as not a real question by Igor Rivin, Gerry Myerson, Andrés E. Caicedo, Will Jagy, S. Carnahan♦ Dec 30 '11 at 11:52It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question. 


The right question is: given a positive integer $n$, what is the largest $r$ such that $n$ nonoverlapping circles of radius $r$ can fit inside a unit square? It's not simply a matter of hexagonal closepacking, because boundary effects are important. There is no known closedform formula, and not likely to be one, but the values are known for $n$ up to 30. See http://en.wikipedia.org/wiki/Circle_packing_in_a_square and http://hydra.nat.unimagdeburg.de/packing/csq/csq.html 


Given a square of side $L$, the area covered by circles, including partial circles, will be $\frac{\pi L^2}{\sqrt{12}}$; since the optimal circle packing density in the plane is $\frac{\pi}{\sqrt{12}}$. Therefore, given circles of radius $r$, the number of circles which fit in the square should be the greatest integer less than $\frac{1}{\sqrt{12}}\frac{L^2}{r^2}$ 

