The number of conjugacy classes in $S_n$ is given by the number of partitions of $n$. Do other families of finite groups have a highly combinatorial structure to their number of conjugacy classes? For example, how much is known about conjugacy classes in $A_n$?
Remember to vote up questions/answers you find interesting or helpful (requires 15 reputation points)
|
21
11
|
|||||||
|
|
28
|
Since The pair The group $\text{GL}(n,q)$ is even more typical. It is a Chevallay group, which means a finite group analogue of a Lie group. All of the infinite sequences of finite simple groups other than $A_n$ and $C_p$ are Chevallay groups. You expect a canonical form that looks something like Jordan canonical form, although it can be rather more complicated. If $G$ is far from simple, i.e., if it has some interesting composition series, then one approach to its conjugacy classes is to chase them down from the conjugacy classes of its composition factors, together with the structure of the extensions. The answer doesn't have to be very tidy. I suppose that finite Coxeter groups give you some exceptions where you do get a tidier answer, just because they all resemble |
||||||
|
You can accept an answer to one of your own questions by clicking the check mark next to it. This awards 15 reputation points to the person who answered and 2 reputation points to you.
|
12
|
For an explicit formula for the size of the conjugacy classes of GL$(n,q)$ (going back to Frobenius and Philip Hall), see equation (1.107) on page 92 of http://math.mit.edu/~rstan/ec/ec1.pdf. (There are formulas for the quantities appearing in (1.107) earlier in the text and in (1.108).) As for the number $\omega^\ast(n,q)$ of conjugacy classes, see Exercise 1.190 on page 156 of the above reference. In particular, for fixed $n$, $\omega^\ast(n,q)$ is a polynomial in $q$ satisfying $$ \sum_{n\geq 0}\omega^\ast(n,q)x^n = \prod_{j\geq 1} \frac{1-x^j}{1-qx^j} $$ $$ \omega^\ast(n,q) = q^n-q^m- q^{m-1}-q^{m-2}-\cdots -q^{\lfloor n/3\rfloor}+O(q^{\lfloor n/3\rfloor-1}), $$ where $m=\lfloor (n-1)/2\rfloor$. |
||||||
|
|
5
|
You will no doubt find this paper interesting: http://archive.numdam.org/ARCHIVE/CM/CM_1972__25_1/CM_1972__25_1_1_0/CM_1972__25_1_1_0.pdf As Greg suggested, for Weyl groups, both conjugacy classes and irreducible representations are known. Beyond this class of examples, and perhaps a few of the other Coxeter groups, my understanding is that there is not a combinatorial description of the conjugacy classes of a finite group. A related difficulty: you know that there are the same number of conjugacy classes as there are irreducible representations in any finite group, as characters form a basis of class functions. In $S_n$, and also in the Coxeter group examples, one can give explicitly a bijection (so there is both a conjugacy class in $S_n$ and an irrep associated to a Young diagram $\lambda$, for instance). For a general group, there is not a general framework for corresponding conjugacy classes to irreps. |
||
|
|

