Following the terminology of Rosenblatt, I will say that a bounded function $f:\mathbb Z\rightarrow\mathbb R$ has a unique mean value if for every pair of finitely additive translation invariant probability measures $\lambda_1,\lambda_2$ on $\mathbb Z$, one has $\int fd\lambda_1=\int fd\lambda_2$.
I will say that $f$ has Fubini's property if for all finitely additive probability measures $\mu,\nu$ on $\mathbb Z$, one has $\int\int f(x+y)d\mu d\nu=\int\int f(x+y)d\nu d\mu$.
Question: Is it true that the two properties above are equivalent?
It is obvious that if $f$ has Fubini's property, then it has also a unique mean value, but the converse is not clear to me. I don't have a real evidence why the two properties should be the same.. let's say, that I am interested in studying the relation between these two properties and I was not able to find a function with a unique mean value which does not have Fubini's property.