If $$ (f \circ g \circ f)(x)=x, \forall x \epsilon \mathbb{R}$$ then show that $$(f \circ g)(x)=( g \circ f)(x)$$
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closed as too localized by Andreas Blass, Simon Thomas, GH, Henry Cohn, J.C. Ottem Nov 30 2011 at 15:56 |

