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What is the quasi-hereditary cover of a quasi-hereditary algebra?

Is the algebra A somehow (always) a quasi-hereditary cover of itself? Or is their a relation to Ringel duality in some way?

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Do you already know R. Rouquier, q-Schur algebras and complex reflection groups? – Martin Brandenburg Nov 8 '11 at 15:24
Yes, any quasi-hereditary algebra is a cover of itself tautologically. Ringel duality has nothing to do with it. – Ben Webster Nov 8 '11 at 16:36
Thanks Ben (and Martin) that's what I thought it should be - very helpful. I'd like to give you the "reputation points" but don't understand how this works. – Chris Bowman Nov 8 '11 at 17:00

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