MathOverflow is a question and answer site for professional mathematicians. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

What is the quasi-hereditary cover of a quasi-hereditary algebra?

Is the algebra A somehow (always) a quasi-hereditary cover of itself? Or is their a relation to Ringel duality in some way?

share|cite|improve this question
    
Do you already know R. Rouquier, q-Schur algebras and complex reflection groups? – Martin Brandenburg Nov 8 '11 at 15:24
1  
Yes, any quasi-hereditary algebra is a cover of itself tautologically. Ringel duality has nothing to do with it. – Ben Webster Nov 8 '11 at 16:36
    
Thanks Ben (and Martin) that's what I thought it should be - very helpful. I'd like to give you the "reputation points" but don't understand how this works. – Chris Bowman Nov 8 '11 at 17:00

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.