## Perpendicular in conformal disk model [closed]

In Euclidean Geometry, we know that from a given point there is an unique line perpendicular to a given line. In conformal disk model, can we do the same thing? Or, more exactly, did there exists such a (geodesic) line, if exists, are they unique? if not, when?

in the above figure, disk A is the conformal model disk. J is the given point, and CD is the given line; I asked how to get the line GF, such that J is on it and GF perpendicular to CD.

-
 May I ask why I can't use the img tag in my question? – van abel Oct 29 2011 at 13:43 This would be a nice question on math.stackexchange.com, but unfortunately it is off topic here. – Dan Petersen Oct 29 2011 at 13:59 This belongs on MSE, as in your other question math.stackexchange.com/questions/76084/… The short answer is yes, one and only one suc geodesic. How to draw it, by compass and straightedge, is a longer story. – Will Jagy Oct 29 2011 at 16:23 the question continued at [link stackexchange][2]. [2]: math.stackexchange.com/questions/77084/… – van abel Oct 30 2011 at 3:56