2

(This question might turn out to be too elementary for this site,
if so I'm sorry, but I can't find the answer anywhere.)


Does there exist a function $\; f : \{z\in \mathbb{C} : |z| < 1\} \to \mathbb{C} \;$

such that $f\hspace{.01 in}$ is a quasiconformal bijection and $f^{-1}$ is quasiconformal?

flag
7 
The plane and a disk are not quasiconformally equivalent, see e.g. page 11 in math.qc.edu/~zakeri/papers/ahl-bers.pdf. Incidentally, the inverse of a quasiconformal map is automatically quasiconformal. – Igor Belegradek Sep 20 2011 at 2:08

Your Answer

Get an OpenID
or

Browse other questions tagged or ask your own question.