# Is the disk quasiconformally isomorphic to the plane?

(This question might turn out to be too elementary for this site,
if so I'm sorry, but I can't find the answer anywhere.)

Does there exist a function $\; f : \{z\in \mathbb{C} : |z| < 1\} \to \mathbb{C} \;$

such that $f\hspace{.01 in}$ is a quasiconformal bijection and $f^{-1}$ is quasiconformal?

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The plane and a disk are not quasiconformally equivalent, see e.g. page 11 in math.qc.edu/~zakeri/papers/ahl-bers.pdf. Incidentally, the inverse of a quasiconformal map is automatically quasiconformal. –  Igor Belegradek Sep 20 '11 at 2:08