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Let $D\subset\mathbb{R}$ be a bounded interval and $f: D\times D \rightarrow \mathbb{R}$ a real-valued analytic function of two variables such that $f\in L_2(D\times D)$. Suppose we have upper bounds on the eigenvalues of the operator,

$ \mathcal{F} : L_2(D)\rightarrow L_2(D), \hspace{.2in} \mathcal{F}(u)(\cdot) = \int_{D}f(\cdot,y)u(y)dy. $

That is $\lambda_m(\mathcal{F})\leq C_m$ for some constant $C_m$ for all $m$. Suppose now, we pick $N\in\mathbb{N}$ real numbers $x_1,\ldots, x_N$ in $D$ and form the matrix, $F\in\mathbb{R}^{N\times N}$ such that,

$ F_{jk} = f(x_j,x_k). $

This is in some sense the discretised version of $\mathcal{F}$. Do we automatically have upper bounds on the eigenvalues of $F$? Ideally, bounds of the form

$ \lambda_m(F) \leq \lambda_m(\mathcal{F}) + \delta, \text{ } 1\leq m\leq N, \text{ } \delta<<1. $

As $N\rightarrow\infty$ and $\{x_k\}_{1\leq k\leq N}$ becomes dense in $D$, do the eigenvalues of $F$ approximate $\mathcal{F}$?

Wrong First attempt

For all $\epsilon>0$ there is an $N$ and points $\{x_k\}_{1\leq k\leq N}$ sufficiently dense in $D$ with non-negative weights $w_1,\ldots, w_N$ such that,

$ \left|\int_{D}\int_{D} f(x,y)u(y)u(x)dxdy - \sum_{j,k=1}^N f(x_j,x_k)u(x_j)w_ju(x_k)w_k\right|<\epsilon. $

Letting $\alpha_j=u(x_j)w_j$ we have,

$ \sum_{j,k=1}^N f(x_j,x_k)\alpha_j\alpha_k < \int_{D}\int_{D} f(x,y)u(y)u(x)dxdy + \epsilon $

Can this be used to bound the Rayleigh quotient and hence the eigenvalues of $F$?

share|improve this question
    
I don't understand why the inequality of your attempt should be true. The right-hand side should involve some norm of $u$ (that in $L^2$ maybe) and the inequality can be valid only for special $u$'s, because $u\mapsto u(x_j)$ is not well-defined on $L^2$. –  Denis Serre Sep 17 '11 at 14:41
    
Yes, you are right. I have no idea how to show this then. :( –  alext87 Sep 17 '11 at 15:09
    
When you perturb your operator (eg by coarsening the grid) how the spectrum changes can be studied with a differential equation. terrytao.wordpress.com/2008/10/28/when-are-eigenvalues-stable might be useful. –  dranxo Sep 17 '11 at 21:09
    
Thanks, rcompton! –  alext87 Sep 19 '11 at 6:51
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