Take the 2-minute tour ×
MathOverflow is a question and answer site for professional mathematicians. It's 100% free, no registration required.

In their classic paper "Class fields of abelian extensions of $\mathbf{Q}$", Mazur and Wiles assert that

"in a cyclotomic $\mathbf{Z}_p$-extension only finitely many primes lie above any prime of $\mathbf{Q}$."

My only other source in learning this material so far has been Washington's "Introduction to Cyclotomic Fields", and the only result along these lines is that such extensions are unramified outside of $p$.

So apparently, all primes lying above $l \neq p$ stop splitting at some finite level $K_n$, after which they remain inert. I've been unable to make much progress is proving this.

How can we see that this statement is true, and what other, more general results do we have about prime decomposition in cyclotomic extensions?

share|improve this question

1 Answer 1

up vote 7 down vote accepted

The point is that the Frobenius at $\ell$ is nontrivial in this extension, so it generates an open subgroup, and the fixed field of this subgroup is precisely the field at which $\ell$ stops splitting.

To see that Frob$_\ell$ is nontrivial, recall that in the full $\mathbb{Z}_p^*$ extension $\mathbb{Q}(\mu_{p^\infty})$, Frob$_\ell$ is simply the element $\ell\in \mathbb{Z}_p^*$, which is clearly nontrivial. The cyclotomic $\mathbb{Z}_p$ extension is obtained by quotienting $\mathbb{Z}_p^*$ by the subgroup $\mu_{p-1}$. This subgroup does not contain $\ell$, so Frob$_\ell$ remains nontrivial in the $\mathbb{Z}_p$-extension.

share|improve this answer
    
By the way, this need not hold for an arbitrary $\mathbb{Z}_p$-extension of a number field. For instance, suppose $K$ is a number field which has a $\mathbb{Z}_p^2$-extension $K_\infty$. Any prime $\ell$ will split completely in the fixed field of Frob$_\ell$, and the galois group of the fixed field over $K$ has $\mathbb{Z}_p$-rank at least one. –  Kevin Ventullo Sep 15 '11 at 19:59
1  
A minor thing: the subgroup Frobenius <<topologically generates>> is open (being closed and non-trivial in $\mathbf{Z}_p$, hence closed and finite index). –  Keenan Kidwell Sep 16 '11 at 23:25

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.