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Is there any theorem to find the eigenvalues of any anti-circulant matrix using the equivalent (with the same first row) circulant matrix. I found out that, for any anti-circulant matrix, the eigenvalues (taken as $\mu$) of the anti-circulant matrix can be written as, \begin{equation} \mu = \pm \mid{\lambda_j}\mid \label{mu_alpha} \end{equation} where $\lambda_j$ is an eigenvalue of 1-circulant matrix with the same first row. This seems valid since any anti-circulant matrix should be symmetric resulting in real eigenvalues.

Can anyone send me a link to any reference which has this proof..? or can you please comment if you think that this should not be correct ?

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Hint: the square of your anti-circulant matrix has the same eigenvectors as the corresponding circulant matrix. –  Gjergji Zaimi Sep 7 '11 at 5:38
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Simul-posted, in a major breach of etiquette, to math.stackexchange, math.stackexchange.com/questions/62466/… –  Gerry Myerson Sep 7 '11 at 6:02
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@Gerry: please don't bite the newbies. While it is better not to simul-post, neither the mathoverflow faq nor the math.stackexchange faq says that explicitly. In any case, a friendly hint would suffice. –  Neil Strickland Sep 7 '11 at 9:03
    
Extremely sorry for simul-post in math.stackexchange, as I didn't know that these two are similar. Can anyone help me to understand what math.stackexchange and math.overflow.. and the differences of them, so that I could post my questions correctly according to the rules.. –  Udara Sep 9 '11 at 1:12

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