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Let $M$ be a closed manifold, $m$ be the normalized volume measure on $M$, and $f:M\to M$ be a $C^2$ transitive Anosov diffeomorphism. Consider the pushforward $f^km$ defined by

----------$f^km(A):=m(f^{-k}A)$ for all measurable subset $A\subset M$.

Then the Birkhoff averages $\nu_k=\frac{1}{k}\sum_{j=0}^{k-1}f^jm$ are probability measures on $M$ for all $k\ge1$. The question is:

  • What can we say about the measure(s) in the set $\mathcal{V}(m)$ of accumulation points of $\{\nu_k:k\ge1\}$?

We know that there exists a unique SRB measure $\mu_+$ for $f$ (and a unique SRB measure $\mu_-$ for $f^{-1}$). Do we have $\mathcal{V}(m)\subset\{\mu_+,\mu_-\}$?

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A quick glance doesn't show me anything in Chernov's survey of invariant measures for hyperbolic dynamical systems unless you have some invariant measure $\mu << m$, in which case the forward and backward measures coincide. –  Steve Huntsman Aug 31 '11 at 6:27
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1 Answer 1

up vote 5 down vote accepted

Yes. In fact, we have $\mathcal{V}(m) = \{\mu_+\}$ whenever $m$ is a probability measure on $M$ that is absolutely continuous with respect to volume. This is shown in (0.4) of "A measure associated with Axiom-A attractors" by David Ruelle, American Journal of Mathematics 98 (1976), 619--654.

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Do you mean "whenever $\mu_+$ is a"? –  Steve Huntsman Aug 31 '11 at 19:29
    
No, $\mu_+$ is the unique SRB measure for $f$. The initial measure $m$ is an arbitrary absolutely continuous probability measure (not necessarily an invariant one!), such as normalised volume. –  Vaughn Climenhaga Aug 31 '11 at 20:17
    
Got it, thanks. –  Steve Huntsman Aug 31 '11 at 20:22
    
Thank you for the reference! –  Pengfei Sep 1 '11 at 1:38
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