no holomorphic function on C\{0} satisfying |f(z)|>=|z|^{-1/2}

no holomorphic function on C\{0} satisfying |f(z)|>=|z|^{-1/2} [closed]

Prove there is no holomorphic function $$f:\mathbb{C}\setminus{0}\rightarrow\mathbb{C}$$s.t.

$$|f(z)|\ge \frac{1}{\sqrt{|z|}}$$

flag	asked Aug 27 2011 at 22:21 AlgRev 21●1

You could ask this question on math.stackexchange.com, a similar site but with a broader scope, where I probably you will get answers. The scope of this site is quite narrow ([advanced] graduate-level mathematics and above) so that your question here will likely be closed; for details please see the FAQ. Also, it would help to see why are you interested in this particular question. Finally, it is always nicer to pose your query as a question and not as an order. – András Bátkai Aug 27 2011 at 22:27

@abatkai:I believe the OP is interested in the question because it is homework. Voting to close. – Igor Rivin Aug 27 2011 at 22:31

This looks like a homework question to me. It would be better to ask this question at math.stackexchange.com. – Daniel Parry Aug 27 2011 at 22:32

Sorry for this. I just got stucked. Will delete this and pay more attention. – AlgRev Aug 27 2011 at 23:08

The question was already asked on math.stackexchange.com a couple of weeks ago: math.stackexchange.com/questions/57532/… – Jonas Meyer Aug 28 2011 at 2:20

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closed as off topic by Noam D. Elkies, Igor Rivin, Will Jagy, Todd Trimble, Yemon Choi Aug 27 2011 at 22:40

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