## Associated primes of weakly Laskerian [closed]

An $R$-module $M$ is said to be weakly Laskerian if the set of associated primes of any quotient module of M is finite.

Let $M$ be a weakly Laskerian $R$-module. Since $M\cong M/0$ then $Ass(M)$ is finite. Is this right?

Thanks.

-
Do you really have any doubt? – Martin Brandenburg Aug 6 2011 at 16:02
Because i think, in the definition of weakly Laskerian module, if $M/N$ is quotient module of $M$, that mean $N$ is a proper submodule of $M$. Thanks. – minhtringuyen Aug 7 2011 at 15:49
Fortunately, zero is a proper submodule of $M$. I think math.stackexchange.com is a more appropriate home for this question. – S. Carnahan Aug 8 2011 at 3:54