MathOverflow will be down for maintenance for approximately 3 hours, starting Monday evening (06/24/2013) at approximately 9:00 PM Eastern time (UTC-4).
1

1

How to find how many zero principal minors does a matrix have? Is there any easy way to compute principal minors?

flag
1 
Please read mathoverflow.net/howtoask. MathOverflow is for questions about research-level mathematics. Perhaps math.stackexchange.com would be a better venue for this question. – David Roberts Jun 20 2011 at 4:21

1 Answer

2

For the incidence matrix $\partial(G)$ of a graph $G$ the answer is easy, as this amounts to knowing how many spanning trees $G$ possess. One can use the matrix-tree theorem to compute the answer by evaluating the determinant of the (reduced) Laplacian matrix $(\partial(G)\partial(G)^T)^{vv}$ of $G$.

For a full rank unimodular matrix $M$ (i.e., all maximal minors are $\pm 1$ or zero) with rational entries there is a related "matrix-tree" type theorem: The number of maximal non-zero minors of $M$ is $\det(M M^T)$. This is probably most useful when the matrix handed to you is a priori unimodular, as above.

For a matrix $M$ which fails to be unimodular the number $\det(MM^T)$ gives an upper bound.

link|flag
Nice answer, but you might want to define "unimodular"... – Igor Rivin Jun 20 2011 at 13:44

Your Answer

Get an OpenID
or

Not the answer you're looking for? Browse other questions tagged or ask your own question.