How is the following formula derived which yields the probability that the sum of the squares of n random draws from the closed interval [1,1] is less than one?
formula: (1/2^n)*pi^(n/2)/(n/2)!
How is the following formula derived which yields the probability that the sum of the squares of n random draws from the closed interval [1,1] is less than one? formula: (1/2^n)*pi^(n/2)/(n/2)! 


Volume of the ball divided by volume of the cube. 

