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Possible Duplicate:
Non-degenerate alternating bilinear form on a finite abelian group

If the radical of a symplectic bilinear form on a finite abelian group is trivial, then how is its order a square?

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2 
 Possible duplicate: see mathoverflow.net/questions/58825/… – Francesco Polizzi May 9 2011 at 11:36
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 The trivial group has order $1 = 1^2$. – Pete L. Clark May 9 2011 at 11:37
@Pete I think "its order" refers to the group, not to the radical – Francesco Polizzi May 9 2011 at 11:39
@Francesco: grammar is on my side on this one. But you are probably right on mathematical grounds, in which case -- as you have pointed out -- the question is an exact duplicate of one you've already answered. – Pete L. Clark May 9 2011 at 11:58
@Pete: you are right, grammar is definitely on your side :) – Francesco Polizzi May 9 2011 at 12:44
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closed as exact duplicate by Pete L. Clark, Francesco Polizzi, Tim Perutz, Daniel Moskovich, Yemon Choi May 10 2011 at 4:39

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