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what is the computational complexity of eigenvalue decomposition for a unitary matrix? is O(n^3) a correct answer?

flag	asked Apr 25 2011 at 9:57 Majid 21●2

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I have some doubts about the relevance of the answers given below. You cannot compute the eigenvalues of a general unitary matrix in finite time. Because, this calculations could be used to solve every polynomial equation with real roots (the real axis is transformed rationally into the unit circle). – Denis Serre Apr 25 2011 at 20:03

Federico Poloni · Answer 1 · 2011-04-25 11:05:05Z UTC

In practice, $O(n^3)$.

In theory, it has the same complexity of matrix multiplication and more or less all the "in practice $O(n^3)$" linear algebra problems, that is, $O(n^\omega)$ for some $2<\omega<2.376$. For this last assertion, see Demmel, Dimitriu, Holtz, "Fast linear algebra is stable".

ght · Answer 2 · 2011-04-25 12:55:51Z UTC

Take a look at the following link (and references therein) for the complexity of various algorithms for common mathematical operations:

Computational Complexity of Mathematical Operations.

In particular, the complexity of the eigenvalue decomposition for a unitary matrix is, as it was mentioned before, the complexity of matrix multiplication which is $O(n^{2.376})$ using the Coppersmith and Winograd algorithm.

unknown (google) · Answer 3 · 2011-04-25 10:58:31Z UTC

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Yep O(n^3) is right

answered Apr 25 2011 at 10:58

unknown (google)
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complexity of eigenvalue decomposition

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