I am reading a text book and am stumped with an example problem.
y = n/p + 2*log(p)
First, y is differentiated with respect to p to give the following result:
dy/dp = -n/p^2 + 2/p
This is simple enough. Although I'm fairly certain you must assume the logarithm to the base e , i.e. is ln the natural logarithm.
The problem then details that you must solve dy/dp = 0 to find p which comes out as p = n/2
The last bit is confusing me, as p is then substituted back into y and the answer is simply given as 2log(n).
substituting the value for p into y, surely this implies:
2 + 2*log(n) - 2*log(2) = 2*log(n)
which implies than the logarithm is actually of base '2' not e as suggested by the original part of the problem. Am I going crazy? or can you change the base like this willy nilly. Has the text book made a mistake here?
