The question that I'd like to answer can be generalized to the following: if $M$ is an orientable 3-manifold and $F$ is a boundary component of $M$ (which may have other boundary components), can an arbitrary diffeomorphism of $F$ with itself be extended to a diffeomorphism of $M$ with itself? I would be very surprised if the answer to the question in this generality is yes, so I'll ask a more specific question.
If $M$ is a complement of a link with 1 or 2 components in $S^3$ and $\sigma:T^2 \to T^2$ is the antipodal map in each component, is there a diffeomorphism $\sigma':M \to M$ that restricts to $\sigma$?
I don't really know how to approach this, but here's a couple thoughts:
1) If I understand right, this question can be reduced to the question of whether the subgroup of the mapping class group of $M$ that preserves $F$ surjects onto the mapping class group of $F$ (since it's my impression that isotopies can be extended from submanifolds).
2) If we lower the dimension by 1 it seems like the answer is yes, at least if the last comment was right. To see this, let $C$ be the boundary component that is to be sent to itself, and write the surface as a quotient of a polygon in $\mathbb R^2$ that is symmetric about the origin. Also, center the boundary component $C$ around the origin, and put the other boundary components symmetrically around the origin. Then the antipodal map in $\mathbb R^2$ induces a diffeomorphism of $F$ with the desired properties.
(I'm not sure about tags - retag as appropriate.)