For which $f \in S(R^n)$, the Schwartz class, $\hat f \in D(R^n)$ ?
Remember to vote up questions/answers you find interesting or helpful (requires 15 reputation points)
|
0
1
|
|||||||||||||||||||
|
|
2
|
Gelfand-Shilov, Generalized Functions, Vol. 1 gives a rather extended discussion of this function class, as well as the corresponding class of distributions. |
||
|
|
You can accept an answer to one of your own questions by clicking the check mark next to it. This awards 15 reputation points to the person who answered and 2 reputation points to you.
|
1
|
Hmmm, Paley wiener provides a way through it. Since we have the result, $\check f $ = $\hat \hat f$ (This result holds for $S(R^n)$,as periodicity of Fourier transform is 4) Let $C$ ={ $ f \in S(R^n)$ | $\hat f \in D(R^n)$ } Then we know that $f \in C$, $\check f $ is an entire function with exponential bound. Then $f$ will also be entire function with exponential bound. Converse of Paley-Wiener Theorem will ensure that this is exactly the class. I hope I didn't make any mistake. :D |
||
|
|

