# Is there a universal coefficient theorem for motivic cohomology?

Is there some kind of universal coefficient theorem for motivic cohomology? In particular, suppose we have a ring morphism $R\to S$, then I would like to know when $$H^{\star\star}(-,S)\simeq H^{\star\star}(-,R)\otimes_{R}S\; ?$$ Does this for example hold when $R$ is a field? In particular, does it hold for $R=\mathbb{Q}$? Or do we need additional assumption on $S$ as well? E.g. that $S$ is a semi-simple or Noetherian $R$-algebra?

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Yes, there is a universal coefficient theorem: the corresponding object of the derived category (of $S$-modules) could be obtained by tensoring by $S$. This is easy, since motivic cohomology is defined as the cohomology of a complex of free modules (over $R$ and $S$, respectively).
To WesleyT: if you don't want to bother with derived categories. you will have to assume that $S$ is flat over $R$. This is certainly true if $R$ is a field. –  Mikhail Bondarko Feb 19 '11 at 19:04