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Statement: If E is a bounded set of real numbers, there exists a G-delta set G such that G contains E and has the same Lebesgue outer measure with E.

I completed the proof for the case that E is countable, but how should I prove this for the case that E is uncountable?

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This question is better suited for the site, math.stackexchange.com, although even there, I suggest providing more details as to what in particular you have tried and are having trouble with. – AppliedSide Feb 16 2011 at 4:38

closed as too localized by Andres Caicedo, Andy Putman, J.C. Ottem, S. Carnahan Feb 16 2011 at 7:23

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