# Is the classification of finite p-groups a smooth problem?

Fix a prime $p$. Then the question is about the difficulty of classifying finite $p$-groups. Originally I was going to ask if this was a "wild" problem but thanks to Joel David Hamkins' answer to question 10481 I now know to ask if it is a smooth problem.

At one time there was a minor industry producing papers which showed that a particular list of invariants did not classify finite $p$-groups so my understanding is that it would be remarkable if this problem was smooth.

Also for each prime $p$ and each $n$ the number of groups of order $p^n$ (up to isomorphism) is finite. This gives a sequence of integers for each $p$. For $p=2,3,5,7$ these sequences appear in OEIS as sequences A000679, A090091, A090130, A090140.

A supplementary question is: Does knowing if the classification is or is not smooth have any bearing on the complexity of these sequences?

-
My sense is that au courant thinking in this area is that p-groups should be classified by coclass rather than by size; if I understand correctly, for each coclass there is a FINITE list of infinite pro-p groups of that coclass, and all the finite ones arise as quotients of these. Of course this doesn't say at all how the classification problem fits into any schema of "wild" vs. "tame"! – JSE Jan 13 '11 at 16:19

If I understood Joel David Hamkins's explanation correctly, then the problem of classifying finite ($p$-)groups is smooth for silly reasons. Attach to each group the following datum: randomly number the elements of a group $G$ from 1 to $|G|$ and consider the set $S_G$ of multiplication tables of $G$ with respect to all possible permutations of the elements, so $(|G|)!$ multiplication tables in total. Two groups $G$ and $H$ are isomorphic if and only if the sets $S_G$ and $S_H$ are equal.

-
I agree with you. This means I did not get the question right. This is saying that I can decide if two $p$-groups are isomorphic without too much difficulty. I wanted to formalise the idea that the classification of finite $p$-groups is difficult. – Bruce Westbury Jan 12 '11 at 18:41
Dear Bruce, I understood what you were getting at, but the hierarchy explained by Joel David Hamkins seems too coarse for that. I think you can safely ask another question about whether there is a good precise way to capture the fact that the classification is difficult. – Alex B. Jan 13 '11 at 1:43

As said in Alex's answer, smoothness is too coarse (=automatic) for classification of finite objects. It concerns equivalence relations on uncountable sets (borel spaces).

On the other hand, there has been great progress on the classification of $p$-groups lately. You can try this 2008 presentation by Bettina Eick (she also has a paper in a 2008 LMS Bulletin whith Leedham-Green, by I dont't have a link).

-

Given a finite $p$-group $G$ of class $c$ and order $p^n$ we say that $G$ has coclass $r=n-c$. In the 80’s Charles Leedham-Green and Mike Newman came up with the 5 coclass conjectures which were striking and counterintuitive. Essentially they say that a $p$-group with small coclass is close to being abelien, e.g. it has derived length that is bounded by a function of $p$ and $r$. The proof of the coclass conjectures is a great achievement. It is due to many mathematicians, let me just mention Charles Leedham-Green, Steve Donkin, Aner Shalev, and Efim Zelmanov who probably contributed the most.

So in some sense $p$-groups are classified by their coclass. The problem is that for the coclass to say something meaningful about a $p$-group the group has to be very large. In other words, if the coclass of $G$ with respect to the order of $G$ is not too small we cannot say much about $G$.

-

1) The classification of p-groups (even p-groups of class 2) is indeed wild over $\mathbb{F}_p$ [V. Sergeichuk, The classification of metabelian p-groups (Russian), Matrix problems, Akad. Nauk Ukrain. SSR Inst. Mat., Kiev, 1977, pp. 150-161.]