# Galois theory: Generalization of Abel's Theorem?

Let $L$ stand for the field obtained by adjoining to ${\Bbb Q}$ all roots of all polynomials of the form $x^n+ax+b$, $a,b\in {\Bbb Q}$.

What polynomials $p$ don't split over $L$? In particular, how low can one make the degree of such a $p$?

Classically, $S_n$ occurs as a Galois group for certain $x^n+ax+b$, $n\geq 5$. That means that obstructions for $p$ splitting over such $L$ must reflect information beyond the Galois group of $p$. So absent a full answer to my question, what candidates does one have for such an obstruction? For example, does the form of the polynomial single out particular representations of $S_n$?

Again, absent a full answer, does the literature contain theorems about polynomials not splitting over similar large extension of ${\Bbb Q}$?

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Utterly trivial remarks (which I make only because they could have been included in the question): any quadratic poly is already of the form $x^2+ax+b$, and "completing the cube" says that any cubic is of the form $x^3+ax+b$ after a linear change of variables, so the smallest degree of such a $p$, if one exists, is at least 4. – Kevin Buzzard Dec 9 '10 at 10:47
Welcome, David! – Jon Bannon Dec 9 '10 at 13:07
A stupid remark on your question: you are asking whether all extensions are contained in an extension of Q generated by a root of $x^n+ax+b$. Say you are more ambitious and ask if equality holds, i.e. if it has a generator of this shape. If so, in particular any extension of Q_p has a generator of this kind and any finite extension as well. If n=6 and p=7, all such polynomials are reducible, so this ambitious generality is not true. But you can ask the original question in finite fields to have a hint of what the answer is... – A. Pacetti Dec 9 '10 at 14:52
I realized in the cold light of morning (but haven't had the time till now to write), that I simply hadn't asked the question I'd intended. I'd simply edit my original question, but now it seems my accidental question has some interest in itself. What I had meant to say was: Let $L$ stand for the smallest extension of ${\Bbb Q}$ closed under the operation of adjoining all roots of polynomials of the form $x^n+ax+b, a,b∈L$. Should I start a new question? – David Feldman Dec 9 '10 at 19:37
Sure, start a new question, and link to it from here. – Scott Morrison Dec 9 '10 at 22:51