Hi,
Let R be commutative regular local ring. Is it true, that for every p \in Spec(R), there is a pprimary Rregular sequence? I.e. an Rregular sequence (x) such that the ideal (x) is pprimary.
Regards, David
Hi, Let R be commutative regular local ring. Is it true, that for every p \in Spec(R), there is a pprimary Rregular sequence? I.e. an Rregular sequence (x) such that the ideal (x) is pprimary. Regards, David 


EDIT: here is a counterexample for the question in general. Let $P \subset R= \mathbb C[[x,y,z,a,b,c]]$ be generated by the $2$ by $2$ minors of the obvious $2$ by $3$ matrix. Then the local cohomology module $H_P^3(R) \neq 0$ (see page 201 of this book), so $P$ can't be a radical of a $2$generated ideal. This is a hard question even for small rings. Let $R=\mathbb C[[x,y,z]]$ and $P$ a prime ideal of height $2$. Your question is the same as asking if the curve $X= \text{Spec} (R/P)$ is always a settheoretic complete intersection. This is widely open even in this case (space curves over complex numbers). An amazing partial result is obtained by CowsikNori: every curve in affine space over a field of characteristic $p>0$ is a settheoretic complete intersection! See this paper by Hartshorne for some relevant references. Of course, there are a lot of papers on this topic to this day, just google the relevant terms in this answer. 

