# Is there a (hope for) formula for a colored HOMFLYPT invariant in terms of HOMFLYPT invariants colored by the fundamental represenations?

Any finite dimensional representation of $SL(n,\mathbb{C})$ can be found as a direct summand inside of some tensor product of the fundamental representations. Since we use finite dimensional representations of the quantum $SL(n)$ to construct the colored HOMFLYPT invariant one can naively hope that the invariants colored by the fundamental representations plus some independent of knot combinatorics would produce you colored HOMFLYPT for any color. How far from true is this naive expectation? Any suggestions or references are very welcomed.

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It depends on what you call "independent of knot combinatorics". Obviously one can get the invariant associated with a representation $V_\lambda\subset V^{\otimes k}$, where $V$ is the fundamental representation, by replacing every strand of the link by $k$ strands (cabling) colored by $V$ and then inserting the projector onto $V_\lambda$; since this projector can be written in terms of Hecke algebra operators (this is the $q$-version of Young symmetrizer), it can be presented graphically as a certain linear combination of $k-k$ tangles. This is what is done in the paper cited by Scott. Not sure if this is the answer you are looking for.
What I would expect is that if we fix a knot and consider the knots invariants indexed by partitions then this system is D-finite or holonomic. For a specific $n$ this was proved by Garoufalidis. I am not aware of any work on the two-variable system.
Thanks Scott. For the avoidance of doubt: this reference is for a simple Lie algebra (but not $G_2$). My point is that there is a two-variable knot invariant for each pair of partitions. I would expect these to be holonomic for a fixed knot. However as far as I know no-one has proved this. –  Bruce Westbury Nov 18 '10 at 18:15