7

2

I'm interested in looking at the details of Gauss' method of determining the sign of the Gauss sum in his "Summatio Quarumdam Serierum Singularium", and I was wondering if anyone knew if there was an English or French translation available at all? I've tried searching on the internet and haven't found anything. Also, are there any modern presentations of the Gauss' method that you would recommend?

Thanks for your help.

flag
2 
D M Bressoud, On the value of Gaussian sums, J Number Theory 13 (1981) 88–94, MR 82b:10046, "gives a new proof, closely paralleling that of Gauss...." – Gerry Myerson Nov 17 2010 at 4:58
Thanks-this looks like it will be really helpful – Lea M Nov 17 2010 at 5:28

3 Answers

9

"The determination of Gauss sums" by Berndt and Evans (Bull. Amer. Math. Soc., Vol. 5, Number 2 (1981), 107-129.) contains an exposition of the original proof due to Gauss. It also includes a short historical outline of various classical and modern proofs due to Dirichlet, Cauchy and others.

link|flag
Thanks for linking to this article – Lea M Nov 17 2010 at 5:29
You're welcome. – Andrey Rekalo Nov 17 2010 at 5:43
2

An English translation of Baumgart's exposition of Gauss's fourth proof can be found here.

link|flag
That looks great-thanks so much for providing the link. – Lea M Dec 7 2010 at 2:05
2

there is a German translation: pages 463-495 in: http://www.amazon.co.uk/Untersuchungen-hohere-arithmetik-Chelsea-Publishing/dp/0821842137

link|flag
1 
(English + French)/2 = German? – Adam Hughes Dec 4 2010 at 1:04
1 
actually, i would say that English $-$ French $\to$ German. – S. Sra Dec 4 2010 at 1:52
Unfortunately I only speak a tiny bit of German (I've just taken a very basic introductory course), but thanks for pointing out that there is a German translation. – Lea M Dec 7 2010 at 2:07

Your Answer

Get an OpenID
or

Not the answer you're looking for? Browse other questions tagged or ask your own question.