Let $G$ be a group and $N$ a normal subgroup of $G$. If one knows a presentation for $G/N$, is it possible to obtain a presentation for $G$ ?
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To get a presentation of the extension $G$, you need:
Here is the precise result, which I have cut and pasted from Proposition 2.5 of my own book "Handbook of Computational Group Theory". Suppose that the group $G$ has a normal subgroup $N$, and that we have presentations $\langle Y \mid S \rangle$ of $N$ and $\langle \overline{X} \mid \overline{R} \rangle$ of $G/N$ on generating sets $Y$ and $\overline{X}$, respectively. Here we shall describe a general recipe for constructing a presentation of $G$ as an extension of $N$ by $G/N$. For each $\overline{x} \in \overline{X}$, choose $x \in G$ with $xN = \overline{x}$, and let $X := \{ x \mid \overline{x} \in \overline{X}\}.$ Then, for any word $\overline{w} \in (\overline{X} \cup \overline{X}^{1})^*$, we can define $w \in (X \cup X^{1})^*$ with $wN = \overline{w}$, by substituting $x$ or $x^{1}$ for each $\overline{x}$ or $\overline{x}^{1}$ occurring in $\overline{w}$. In particular, for each $\overline{r} \in \overline{R}$ there is a corresponding word $r$, and then $\overline{r} = 1_{G/N}$ implies that $r \in N$, so in the group $G$ we have $r =_G w_r$, for some word $w_r \in (Y \cup Y^{1})^*$. Let $R$ be the set $\{ rw_r^{1} \mid \overline{r} \in \overline{R} \}$. For each $y \in Y$ and $x \in X$, we have $x^{1}yx \in N$, so $x^{1}yx =_G w_{xy}$ for some word $w_{xy} \in (Y \cup Y^{1})^*$. Let $T$ be the set $\{ x^{1}yxw_{xy}^{1} \mid x \in X,\,y \in Y \}$. Then $\langle X \cup Y \mid R \cup S \cup T \rangle$ is a presentation of $G$. 


I think it's pretty clear that you also need a presentation for $N$ and to understand the map $G\to G/N$. (It's hard to say for sure, as you don't say how $G$ and $N$ are given to you.) Given that information, you can do it: see, for instance, Lemma 2.1 of this paper. 

