# Help with Griffiths & Harris, Surfaces

I believe to have found a typo in Griffiths & Harris.

In the chapter on surfaces, section Rational Surfaces 1, I am trying to read the result that a holomorphic vector bundle over $\mathbb{P}^1_{\mathbb{C}}$ is a sum of invertible bundles.

What is the exact sequence that shows up at the start of his argument? Mine only has 2 terms and involves the fibres of E and H, which doesn't really make sense to me.

Any help would be appreciated.

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Consider the "term" in that exact sequence that makes no sense because it's two terms written next to each other. Now put an arrow between them. Presto---you're back on track! –  Kevin Buzzard Nov 1 '10 at 13:17
Hi Robert, There are many many typos in Griffiths and Harris. I've only gone through Chapters 0 and 1, but marked up my book in many places. I can show you next term when you're in my Kahler manifolds class. –  Spiro Karigiannis Nov 1 '10 at 13:25
For the proof in the algebraic case, and a clever remark, try section 10.5, page 129, of Algebraic varieties, by George Kempf. –  roy smith Nov 1 '10 at 15:41
(I have removed some gendered language. I hope I have not changed any intended meanings.) –  Theo Johnson-Freyd Nov 1 '10 at 18:20

Let $H$ be the divisor corresponding to the point $x\in \mathbb{P}^1$. Tensoring the exact sequence $$0\to O_{\mathbb{P}^1}(-H)\to O_{\mathbb{P}^1}\to O_x\to 0.$$ with $E\otimes H^k$, gives $$0\to O_{\mathbb{P}^1}(E\otimes H^{k-1})\to O_{\mathbb{P}^1}(E\otimes H^{k})\to E_x\otimes H_x^{k}\to 0.$$Here GH writes $E_x\otimes H_x^{k}$ for $E\otimes H^k\otimes O_x$, or what is the same, the fiber of $E\otimes O(H^{k})$ over $x$.