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Is every unit norm Bessel sequence in a Hilbert space a finite union of separated ones? Is every unit norm separated sequence a finite union of uniformly minimal (minimal with uniformly bounded biorthogonal vectors) ones?

edited Sep 15 2010 at 18:38

Matthew Daws
5,529●1●8●29

asked Sep 15 2010 at 17:55

MiM
11●1

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It might be worth defining these terms... – Matthew Daws Sep 15 2010 at 18:38

Unit norm means each vector is of norm 1. Separated means that there is a constant $c>0$ s.t. the distance between any two vectors is $>c$. Minimal means that none of the vectors is in the closed span of the others. – MiM Sep 15 2010 at 19:23

And a Bessel sequence? – Yemon Choi Sep 15 2010 at 21:57

$f_n$ is a Bessel sequence if $\sum|<f|f_n>|^2\leq \|f\|^2$ for all vectors $f$. – MiM Sep 15 2010 at 22:21

instead of $\leq \|f\|^2$ it should be $\leq C\|f\|^2$. Sorry. – MiM Sep 15 2010 at 22:23

Bill Johnson · Answer 1 · 2010-09-16 11:34:55Z UTC

Your questions are weakenings of the Feichtinger conjecture, which is equivalent to the Kadison-Singer problem. See

http://www.aimath.org/WWN/kadisonsinger/FrameProblems.pdf

and the references therein.

Your second question is Problem 2.2 there.

The questions themselves are not obvious ones. Why did you ask them?

Bessel sequence, uniformly minimal, separated

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