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Apart from partial differential and partial difference operators, what other partial operators are there?

I was thinking about multivariable situations in which you can focus on single variables and combine several single variables at a time e.g. fxxy. I suppose you could invent any number of such things e.g. max_compl ij{ a, b, c, ...} where a,b,c are vectors and max_compl i produces a new set without the vector(s) whose ith component is larger than that of the other vectors in the set, and here max_compl is the partial version of the ordinary version that would work on a set of scalars. I was just wondering after partial differential operators what would be the most common such operators.

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 I am voting to close (“not a real question”). If you are asking what other operators have “partial” in their name, that seems somewhat silly. And if you think of partial-ness as some property that an operator may or may not have, well I don't think such a property exists, so the question becomes meaningless. – Harald Hanche-Olsen Sep 15 2010 at 16:26
I've edited the question to elaborate on what I was thinking. – unknown (yahoo) Sep 15 2010 at 17:06
This seems to me a kind of common "inverse question": what would be the question for this answer? or what object should have this name?. If things go the right way, one comes into an object worth of study, and of a name. In the present case, say, an operator acting on functions of several variables, taking them as functions of say one of the variables only, while the remaining variables are seen as parameters. At this point one may ask: given that the simpler operator acting on 1-variable functions is called blabla-operator, how should I call the above operator on $n$-variable functions? – Pietro Majer Sep 15 2010 at 17:53
Anyway, as to your last question, I found as number N of Google's answers: partial differential operator(s), N=23,000,000; partial difference operator(s), N=28,000; partial integral operator(s), N=12,000; partial composition operator(s), N=231; partial convolution operator(s), N=4. – Pietro Majer Sep 15 2010 at 18:10

closed as not a real question by Steve Huntsman, Harald Hanche-Olsen, Qiaochu Yuan, Will Jagy, fedja Sep 15 2010 at 16:39

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