Pretty straitforward: If a field has a metric in which it is complete can it have a metric in which it is not complete? By metric I mean field norm of course
How about the algebraic closure of the $p$adics $\mathbb{Q}_p^{\mathrm{alg}}$. This is not complete under the $p$adic metric, but it is isomorphic as a field to the complex numbers $\mathbb{C}$ which is complete under the standard metric (as both fields are algebraically closed of characteristic zero with the same transcendence degree over $\mathbb{Q}$ (assuming AC of course)). But if you want the second field to have nonarchimedean norm, take the $p$adic complex field $\mathbb{C}_p$ (the completion of $\mathbb{Q}_p^{\mathrm{alg}}$). 


I claim that, for a field $K$, the following are equivalent: Some of these facts are proved in http://math.uga.edu/~pete/8410Chapter2v2.pdf (see e.g. Theorem 1). Let me prove here that (iv) $\implies$ (iii), which answers the OP's question in a rather definitive way. 1) Suppose first that $K$ has characteristic $0$. Then $K$ contains $\mathbb{Q}$, which admits the $p$adic valuations $v_p$. By Theorem 1 of loc. cit., each $v_p$ extends to a valuation on $K$. Now suppose that $K$ has characteristic $p$ and contains an element $t$ which is not algebraic over $\mathbb{F}_p$. Thus $K$ contains the rational function field $\mathbb{F}_p(t)$, which carries infinitely many inequivalent nontrivial valuations $v_P$ corresponding to the irreducible polynomials $P \in \mathbb{F}_p[t]$ (and one more corresponding to the point at infinity on the projective line). 2) (F.K. Schmidt) If a field $K$ is complete with respect to two inequivalent rank one valuations, it is algebraically closed and uncountable. See e.g. Theorem 24 of http://math.uga.edu/~pete/8410Chapter3.pdf 3) So we are reduced to the case in which $K$ is algebraically closed and uncountable. Then $K$ is isomorphic to the algebraic closure of $K(t)$. If we give $K$ the trivial valuation and $K(t)$ the Gauss norm $v$, then the algebraic closure of $K(t)$ has infinite degree over $K(t)$ so any extension of $v$ to the algebraic closure is not complete. The image of the Gauss norm $v$ under the group $PGL_2(K)$ of linear fractional transformations gives us infinitely more pairwise inequivalent valuations. 

